android – 自定义选择意图并排除我自己的活动

2019年8月4日 122次阅读

我有活动,在
android清单中设置为默认动作ACTION_VIEW,我想让活动接收我的应用程序的http,https等url类型的方案.请参阅下面的代码

<activity
        android:name="com.test.ui.LinkLauncherActivity"
        android:label="@string/app_name" 
        android:excludeFromRecents="true"
        android:screenOrientation="portrait"
        android:theme="@android:style/Theme.NoDisplay">
        <intent-filter>
            <action android:name="android.intent.action.VIEW" />
            <category android:name="android.intent.category.DEFAULT" />
            <category android:name="android.intent.category.BROWSABLE" />
            <data android:scheme="http" />
            <data android:scheme="https"/>
        </intent-filter>
    </activity>

>现在从我的应用程序中我可以选择共享链接,为此我
想要打开选择意图与选定的应用程序应该只
在选择对话框中列出的排除我自己的应用程序
>目前当我通过动作查询包管理器时
(ACTION_VIEW)它将返回我的应用程序列表
找到我的包名我只是忽略它并打开选择意图但是
它仍然显示我在自定义共享意图对话框中的应用程序.
>是否由于我在上面的代码中将类别定义为清单中的默认值？
>让我们分享自定义意图代码

Uri uriUrl = Uri.parse(mlm.getHitUrl());
//get package manager
PackageManager pm = getPackageManager();

Intent viewIntent = new Intent(Intent.ACTION_VIEW,uriUrl);

List<ResolveInfo> resInfo = pm.queryIntentActivities(viewIntent, 0);

List<LabeledIntent> intentList = new ArrayList<LabeledIntent>(resInfo.size() - 1); 

for (int i = 0; i < resInfo.size(); i++) 
{
    // Extract the label, append it, and repackage it in a LabeledIntent 
    ResolveInfo ri = resInfo.get(i);

    String packageName = ri.activityInfo.packageName;

    Log.d(getTag(),String.format("PackageName : %2s",packageName));

    if (!TextUtils.equals(packageName,"my application packageName")) {

        Intent intent = new Intent(Intent.ACTION_VIEW,uriUrl);
        intent.setPackage(packageName);
        intentList.add(new LabeledIntent(intent, packageName, ri.loadLabel(pm), ri.icon));
    }
}

// convert intentList to array 
LabeledIntent[] extraIntents = intentList.toArray( new LabeledIntent[ intentList.size() ]);

Intent openInChooser = Intent.createChooser(viewIntent, getResources().getString(R.string.intent_title_open_link));

openInChooser.putExtra(Intent.EXTRA_INITIAL_INTENTS, extraIntents);

openInChooser.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK);

startActivity(openInChooser);

>上面的代码仍然显示我在intent对话框中的应用程序.

最佳答案 试试这个代码.

Intent intent = new Intent();

    intent.setAction(android.content.Intent.ACTION_VIEW);

    MimeTypeMap mime = MimeTypeMap.getSingleton();

    String ext = file.getName().substring(file.getName().indexOf(".")+1);

    String type = mime.getMimeTypeFromExtension(ext);

    intent.setDataAndType(Uri.fromFile(file),type);

    PackageManager packageManager = activity.getPackageManager();

    List<ResolveInfo> activities = packageManager.queryIntentActivities(intent, 0);

    String packageNameOfAppToHide = "com.test.app";

    ArrayList<Intent> targetIntents = new ArrayList<Intent>();

    for (ResolveInfo currentInfo : activities) {

            String packageName = currentInfo.activityInfo.packageName;

        if (packageNameToHide.equals(packageName)) {

            Intent targetIntent = new Intent(android.content.Intent.ACTION_VIEW);

            targetIntent.setDataAndType(Uri.fromFile(file),type);
            targetIntent.setPackage(packageName);
            targetIntents.add(targetIntent);
        }
    }
    if(targetIntents.size()>0) {

        Intent chooserIntent = Intent.createChooser(targetIntents.remove(0), "Open file with");

        chooserIntent.putExtra(Intent.EXTRA_INITIAL_INTENTS, targetIntents.toArray(new Parcelable[] {}));

        activity.startActivity(chooserIntent);
    }
    else
        Toast.makeText(this, "No app found", Toast.LENGTH_SHORT).show();

com.test.app是您的应用程序的包名称.

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