我花了一些时间来为iOS(设备和模拟器)编译用于arm64和x86_64架构的LibiCal.认为它可能对其他人有用.以下是我编译LibiCal-1.0的步骤.我从下面的链接中获取了代码
并修改了一点以适应Xcode 5.1
1)从下面的URL下载LibiCal
http://sourceforge.net/projects/freeassociation/
解开并进入libCal-1.0文件夹.然后跑
./bootstrap
(需要从http://www.jattcode.com/installing-autoconf-automake-libtool-on-mac-osx-mountain-lion/下载制作工具)
使用以下脚本
#!/bin/sh
# SEE: http://www.smallsharptools.com/downloads/libical/
PATH="`xcode-select -print-path`/usr/bin:/usr/bin:/bin"
# set the prefix
PREFIX=${HOME}/Library/libical
OUTPUTDIR=../libical-build
export ARCH=arm64
# Select the desired iPhone SDK
export SDKVER="7.1"
export DEVROOT=`xcode-select --print-path`
export SDKROOT=$DEVROOT/Platforms/iPhoneOS.platform/Developer/SDKs/iPhoneOS${SDKVER}.sdk
export IOSROOT=$DEVROOT/Platforms/iPhoneOS.platform
# Includes
# find $DEVROOT -type d -name include|grep -i iphone|grep -i arm-apple-darwin|grep -vi install-tools|grep -vi simulator
# $SDKROOT/usr/include
# $DEVROOT/Platforms/iPhoneOS.platform/Developer/usr/llvm-gcc-4.2/lib/gcc/arm-apple-darwin10/4.2.1/include
if [ ! -d $DEVROOT ]
then
echo "Developer Root not found! - $DEVROOT"
exit
fi
echo "DEVROOT = $DEVROOT"
if [ ! -d $SDKROOT ]
then
echo "SDK Root not found! - $SDKROOT"
exit
fi
echo "SDKROOT = $SDKROOT"
if [ ! -d $IOSROOT ]
then
echo "iOS Root not found! - $IOSROOT"
exit
fi
echo "IOSROOT = $IOSROOT"
# finding ld
# find $DEVROOT -type f -name ld|grep -i iphone
# Set up relevant environment variables
export CPPFLAGS="-arch $ARCH -I$SDKROOT/usr/include -I$IOSROOT/Developer/usr/llvm-gcc-4.2/lib/gcc/arm-apple-darwin10/4.2.1/include"
export CFLAGS="$CPPFLAGS -pipe -no-cpp-precomp -isysroot $SDKROOT"
export CXXFLAGS="$CFLAGS"
export LDFLAGS="-L$SDKROOT/usr/lib/ -arch $ARCH"
export CLANG=$DEVROOT/Toolchains/XcodeDefault.xctoolchain/usr/bin/clang
#export CC=$IOSROOT/Developer/usr/bin/arm-apple-darwin10-llvm-gcc-4.2
#export CXX=$IOSROOT/Developer/usr/bin/arm-apple-darwin10-llvm-g++-4.2
export CC=$CLANG
export CXX=$CLANG
export LD=$IOSROOT/Developer/usr/bin/ld
export AR=$IOSROOT/Developer/usr/bin/ar
export AS=$IOSROOT/Developer/usr/bin/as
export LIBTOOL=$IOSROOT/usr/bin/libtool
export STRIP=$IOSROOT/Developer/usr/bin/strip
export RANLIB=$IOSROOT/Developer/usr/bin/ranlib
HOST=arm-apple-darwin10
if [ ! -f $CC ]
then
echo "C Compiler not found! - $CC"
exit
fi
if [ ! -f $CXX ]
then
echo "C++ Compiler not found! - $CXX"
exit
fi
if [ ! -f $LD ]
then
echo "Linker not found! - $LD"
exit
fi
if [ -d $OUTPUTDIR/$ARCH ]
then
rm -rf $OUTPUTDIR/$ARCH
fi
find . -name \*.a -exec rm {} \;
make clean
./configure --prefix=$PREFIX --disable-dependency-tracking --host $HOST CXX=$CXX CC=$CC LD=$LD AR=$AR AS=$AS LIBTOOL=$LIBTOOL STRIP=$STRIP RANLIB=$RANLIB
make -j4
# copy the files to the arch folder
mkdir -p $OUTPUTDIR
mkdir -p $OUTPUTDIR/$ARCH
cp `find . -name \*.a` $OUTPUTDIR/$ARCH/
xcrun -sdk iphoneos lipo -info $OUTPUTDIR/$ARCH/*.a
echo $ARCH DONE
echo "See $OUTPUTDIR"
修改行:11“export ARCH = arm64”以获得所需的体系结构,即arm64,armv7,armv7s.
这应该在../libical-build文件夹中为所需的体系结构创建垃圾箱.
为x86_64构建.
使用以下命令运行x86_64的get build.
tar -xovf libical-1.0.tar
cd libical-1.0
./bootstrap
./configure
make
这应该在文件夹src / libical / .libs / libical.a中创建libical.a.
创建一个胖库
使用下面的命令来构建胖库. (请使用适当的脂肪指令).
export DEVROT=/Applications/Xcode.app/Contents/Developer/Platforms/iPhoneOS.platform/Developer/usr/bin/lip
$DEVROOT/usr/bin/lipo
-arch arm64 $OUTPUTDIR/armv6/libical.a
-arch i386 $OUTPUTDIR/i386/libical_Simulator.a
-arch armv7 $OUTPUTDIR/x86_64/libical.a
-arch armv7s $OUTPUTDIR/x86_64/libical.a
-arch x86_64 $OUTPUTDIR/x86_64/libical.a
-create -output $OUTPUTDIR/libical_fat_universal.a
请设置适当的OUTPUTDIR环境变量.
我希望上面会帮助一些想要快速构建iOS的Libical的人.
最佳答案 我找到了解决问题的方法.我做的主要是添加以下开关
-mios-simulator-version-min=7.0
这是我当前的脚本版本:
#!/bin/sh
set -o xtrace
# SEE: http://www.smallsharptools.com/downloads/libical/
PATH="`xcode-select -print-path`/usr/bin:/usr/bin:/bin"
if [ ! -n "$ARCH" ]; then
export ARCH=armv7
fi
# Select the desired iPhone SDK
export SDKVER="7.1"
export DEVROOT=`xcode-select --print-path`
if [ "i386" = $ARCH ] || [ "x86_64" = $ARCH ]; then
export SDKROOT=$DEVROOT/Platforms/iPhoneSimulator.platform/Developer/SDKs/iPhoneSimulator${SDKVER}.sdk
export MIOS="-mios-simulator-version-min=7.0"
else
export SDKROOT=$DEVROOT/Platforms/iPhoneOS.platform/Developer/SDKs/iPhoneOS${SDKVER}.sdk
export MIOS=""
fi;
export IOSROOT=$DEVROOT/Platforms/iPhoneOS.platform
if [ ! -d $DEVROOT ]
then
echo "Developer Root not found! - $DEVROOT"
exit 1
fi
echo "DEVROOT = $DEVROOT"
if [ ! -d $SDKROOT ]
then
echo "SDK Root not found! - $SDKROOT"
exit 1
fi
echo "SDKROOT = $SDKROOT"
if [ ! -d $IOSROOT ]
then
echo "iOS Root not found! - $IOSROOT"
exit 1
fi
echo "IOSROOT = $IOSROOT"
# Set up relevant environment variables
export CPPFLAGS="-arch $ARCH -I$SDKROOT/usr/include $MIOS --debug"
export CFLAGS="$CPPFLAGS -pipe -no-cpp-precomp -isysroot $SDKROOT "
export CXXFLAGS="$CFLAGS"
export LDFLAGS="-L$SDKROOT/usr/lib/ -arch $ARCH"
export CLANG=$DEVROOT/Toolchains/XcodeDefault.xctoolchain/usr/bin/clang
export CC=$CLANG
export CXX=$CLANG
export LD=$IOSROOT/Developer/usr/bin/ld
export AR=$IOSROOT/Developer/usr/bin/ar
export AS=$IOSROOT/Developer/usr/bin/as
export LIBTOOL=$IOSROOT/usr/bin/libtool
export STRIP=$IOSROOT/Developer/usr/bin/strip
export RANLIB=$IOSROOT/Developer/usr/bin/ranlib
export LIPO="xcrun -sdk iphoneos lipo"
export HOST=arm-apple-darwin10
if [ ! -f $CC ]
then
echo "C Compiler not found! - $CC"
exit
fi
if [ ! -f $CXX ]
then
echo "C++ Compiler not found! - $CXX"
exit
fi
if [ ! -f $LD ]
then
echo "Linker not found! - $LD"
exit
fi
if [ -d $OUTPUT_DIR/$ARCH ]
then
rm -rf $OUTPUT_DIR/$ARCH
fi
find ./src -name \*.a -exec rm {} \;
make clean
./configure --prefix="$OUTPUT_DIR" --disable-dependency-tracking --host $HOST CXX=$CXX CC=$CC LD=$LD AR=$AR AS=$AS LIBTOOL=$LIBTOOL STRIP=$STRIP RANLIB=$RANLIB
make -j4
# copy the files to the arch folder
mkdir -p $OUTPUT_DIR
mkdir -p $OUTPUT_DIR/$ARCH
cp `find . -name \*.a` $OUTPUT_DIR/$ARCH/
cp config.log $OUTPUT_DIR/$ARCH/config.log
$LIPO -info $OUTPUT_DIR/$ARCH/*.a
echo $ARCH DONE
echo "See $OUTPUT_DIR"
我已经开始为这个库构建一个Objective C包装器,你可以看到它的进展
https://github.com/ahalls/XbICalendar我该项目可以使用一些眼球提出建议甚至一些帮助.