我忙于GS1-128并且希望使用RegEx匹配扫描的条形码.我目前有以下表达式:
^(01)(12345678)(\d{5})\d(11|17)(\d{2}[0-1]\d[0-3]\d)(10|21)(\d{1,20})(30)(\d{1,20})
这成功地匹配条形码(01)12345678123450(11)130500(21)1234567890(30)42,将其分成以下组:
> 01 – GTIN
> 12345678 – 公司代码(虚拟) – 8位数
> 12345 – partcode(哑) – 5位数
> 11或17 – 生产日期/失效日期
> 130500 – 日期 – 6位数
> 10或21 – 批次/序列号
> 1234567890 – 1到20个字符
> 30 – 项目数(可选)
> 42 – 1到8个字符(可选)
现在,我有时会有条形码没有AI项目的数量; 30.我似乎无法弄清楚如何将这一点用于我的正则表达式.每当我制作第8组& 9可选,对于包含AI 30的所有条形码,这些组的内容将被抛入组7.
如何防止AI 30与AI 21/10分组?
测试用例:
(01)12345678654320(11)120500(21)1234567890应该给出以下匹配:
> 01
> 12345678
> 65432
> 11
> 120500
> 21
> 1234567890
>没有比赛
>没有比赛
(01)12345678124570(17)130700(10)30567(30)50应该给出以下匹配:
> 01
> 12345678
> 12457
> 17
> 130700
> 10
> 30567
> 30
> 50
(01)12345678888880(11)140200(21)66503042(30)100应该给出以下匹配:
> 01
> 12345678
> 88888
> 11
> 140200
> 21
> 66503042
> 30
> 100
请注意,括号仅用于显示AI开始的位置,条形码本身省略了这些.
最佳答案 试试这个:
^(?<gtin>\(01\))(?<comp_code>12345678)(?<part_code>\d{5})0?(?<pd_ed>\((?:11|17)\))(?<date>\d{6})(?<bat_no>\((?:21|10)\))(?<data_req>\d{1,20}?)\b(?<count>(?:\(30\))?)(?<data_opt>(?:\d{1,8})?)$
上面的表达式应该匹配以下所有项:
(01)12345678654320(11)120500(21)1234567890
(01)12345678124570(17)130700(10)30567(30)50
(01)12345678888880(11)140200(21)66503042(30)100
说明:
<!--
^(?<gtin>\(01\))(?<comp_code>12345678)(?<part_code>\d{5})0?(?<pd_ed>\((?:11|17)\))(?<date>\d{6})(?<bat_no>\((?:21|10)\))(?<data_req>\d{1,20}?)\b(?<count>(?:\(30\))?)(?<data_opt>(?:\d{1,8})?)$
Assert position at the beginning of the string «^»
Match the regular expression below and capture its match into backreference with name “gtin” «(?<gtin>\(01\))»
Match the character “(” literally «\(»
Match the characters “01” literally «01»
Match the character “)” literally «\)»
Match the regular expression below and capture its match into backreference with name “comp_code” «(?<comp_code>12345678)»
Match the characters “12345678” literally «12345678»
Match the regular expression below and capture its match into backreference with name “part_code” «(?<part_code>\d{5})»
Match a single digit 0..9 «\d{5}»
Exactly 5 times «{5}»
Match the character “0” literally «0?»
Between zero and one times, as many times as possible, giving back as needed (greedy) «?»
Match the regular expression below and capture its match into backreference with name “pd_ed” «(?<pd_ed>\((?:11|17)\))»
Match the character “(” literally «\(»
Match the regular expression below «(?:11|17)»
Match either the regular expression below (attempting the next alternative only if this one fails) «11»
Match the characters “11” literally «11»
Or match regular expression number 2 below (the entire group fails if this one fails to match) «17»
Match the characters “17” literally «17»
Match the character “)” literally «\)»
Match the regular expression below and capture its match into backreference with name “date” «(?<date>\d{6})»
Match a single digit 0..9 «\d{6}»
Exactly 6 times «{6}»
Match the regular expression below and capture its match into backreference with name “bat_no” «(?<bat_no>\((?:21|10)\))»
Match the character “(” literally «\(»
Match the regular expression below «(?:21|10)»
Match either the regular expression below (attempting the next alternative only if this one fails) «21»
Match the characters “21” literally «21»
Or match regular expression number 2 below (the entire group fails if this one fails to match) «10»
Match the characters “10” literally «10»
Match the character “)” literally «\)»
Match the regular expression below and capture its match into backreference with name “data_req” «(?<data_req>\d{1,20}?)»
Match a single digit 0..9 «\d{1,20}?»
Between one and 20 times, as few times as possible, expanding as needed (lazy) «{1,20}?»
Assert position at a word boundary «\b»
Match the regular expression below and capture its match into backreference with name “count” «(?<count>(?:\(30\))?)»
Match the regular expression below «(?:\(30\))?»
Between zero and one times, as many times as possible, giving back as needed (greedy) «?»
Match the character “(” literally «\(»
Match the characters “30” literally «30»
Match the character “)” literally «\)»
Match the regular expression below and capture its match into backreference with name “data_opt” «(?<data_opt>(?:\d{1,8})?)»
Match the regular expression below «(?:\d{1,8})?»
Between zero and one times, as many times as possible, giving back as needed (greedy) «?»
Match a single digit 0..9 «\d{1,8}»
Between one and 8 times, as many times as possible, giving back as needed (greedy) «{1,8}»
Assert position at the end of the string (or before the line break at the end of the string, if any) «$»
-->
编辑
省略的逃脱的parens:
^(?<gtin>01)(?<comp_code>12345678)(?<part_code>\d{5})0?(?<pd_ed>(?:11|17))(?<date>\d{6})(?<bat_no>(?:21|10))(?<data_req>\d{1,20}?)\b(?<count>(?:30)?)(?<data_opt>(?:\d{1,8})?)$