Symfony2：WHERE子句中的Doctrine子查询,包括LIMIT

2019年8月4日 525次阅读

我正在尝试将此SQL转换为DQL或查询构建器变体的外观.

select *
  from project_release r
 where (select s.title as status_name
          from release_status_log l
          left join release_status s
            on l.release_status_id = s.id
         where l.release_id = r.id
         order by l.created_at desc
         limit 1
       ) not in ('Complete', 'Closed')
;

从Release实体的存储库类内部,我试过这个

return $this->getEntityManager()->createQuery("
    select r.*
      from MyBundle:Release r
     where (select s.title
              from MyBundle:ReleaseStatusLog l
              join l.status s
             where l.release = r
             order by l.createdAt desc
             limit 1
           ) IN ('Complete','Closed')
     order by r.release_date ASC
     limit 10
")->getArrayResult();

这给出了错误

[Syntax Error] line 0, col 265: Error: Expected
Doctrine\ORM\Query\Lexer::T_CLOSE_PARENTHESIS, got ‘limit’

这是指子查询中的限制1.

那么我试过这个

return $this
  ->createQueryBuilder('r')
  ->select('r.*')
  ->where("(select s.title
              from MyBundle:ReleaseStatusLog l
              join l.status s
             where l.release = r
             order by l.created_at desc
             limit 1
           ) $inClause ('Complete', 'Closed')
  ")
  ->setMaxResults( $limit )
  ->orderBy('release_date', 'ASC')
  ->getQuery()
  ->getArrayResult()
;

这给出了同样的错误.如何在父查询中执行每行限制为1行的子查询？

> Symfony 2.0.15
>学说2.1.7
> PHP 5.3.3
> MySQL 5.1.52

最佳答案 我现在有一个解决方案.我最终回退到本机查询系统,结果集映射来自问题中的实体.

它不是一个很好的解决方案,但它可以工作,直到我看到另一个解决方案,它是这种类型的WHERE子句的唯一选择.

这就是我的finder方法现在的样子

/**
 * Finds Releases by their current status
 *
 * @param array $statuses      White-list of status names
 * @param boolean $blackList   Treat $statuses as a black-list
 * @param integer $limit       Limit the number of results returned
 * @param string $order        Sort order, ASC or DESC
 *
 * @throws \InvalidArgumentException
 *
 * @return array <Release>
 */
public function findByCurrentStatus( array $statuses, $blackList=false, $limit=null, $order='ASC' )
{
  if ( empty( $statuses ) )
  {
    throw new \InvalidArgumentException( "Must provide at least one status" );
  }
  $inClause = $blackList ? 'not in' : 'in';

  $rsm = new ResultSetMappingBuilder($this->getEntityManager());
  $rsm->addRootEntityFromClassMetadata('MyBundle:Release', 'r');

  $SQL = "
    select *
      from project_release r
     where (select s.title as status_name
              from release_status_log l
              left join release_status s
                on l.release_status_id = s.id
             where l.release_id = r.id
             order by l.created_at desc
             limit 1
           ) $inClause ('" . implode( "','", $statuses ) . "')
    order by r.release_date $order
  ";

  if ( $limit )
  {
    $SQL .= " limit $limit";
  }

  return $this
    ->getEntityManager()
    ->createNativeQuery( $SQL, $rsm )
    ->getResult()
  ;
}

我有点厌恶回到构建一个字符串的查询,但哦,好吧.哦,对于你的鹰眼,$status不是来自用户数据,所以这里没有SQL注入漏洞;)

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