c# – MVC3按属性名称的本地化显示名称属性

2023年9月26日 267次阅读

我最近学习了如何使用以下文章为我的模型的属性创建本地化的显示名称：
Simplified localization for DataAnnotations

我现在试图通过从构造函数中删除参数来进一步推动它.
意思而不是拥有这个

public class User
{
    [Required]
    [LocalizedDisplayNameAttribute("User_Id")]
    public int Id { get; set; }

    [Required]
    [StringLength(40)]
    [LocalizedDisplayNameAttribute("User_FirstName")]
    public string FirstName { get; set; }

    [Required]
    [StringLength(40)]
    [LocalizedDisplayNameAttribute("User_LastName")]
    public string LastName { get; set; }
}

我想要这个

public class User
{
    [Required]
    [LocalizedDisplayNameAttribute]
    public int Id { get; set; }

    [Required]
    [StringLength(40)]
    [LocalizedDisplayNameAttribute]
    public string FirstName { get; set; }

    [Required]
    [StringLength(40)]
    [LocalizedDisplayNameAttribute]
    public string LastName { get; set; }
}

现在问题是如何让这个课：

public class LocalizedDisplayNameAttribute : DisplayNameAttribute
{
    private PropertyInfo _nameProperty;
    private Type _resourceType;

    public LocalizedDisplayNameAttribute(string className, string propertyName)
        : base(className + (propertyName == null ? "_Class" : ("_" + propertyName)))
    {

    }

    public override string DisplayName
    {
        get
        {
            return LanguageService.Instance.Translate(base.DisplayName) ?? "**" + base.DisplayName + "**";
        }
    }
}

知道我的属性名称,而不必在构造函数中指定它.

最佳答案 这对我来说可以.

[DataType(DataType.EmailAddress, ErrorMessageResourceName = "ThisFieldIsRequired", ErrorMessageResourceType = typeof(Resource))]
        [Required(ErrorMessageResourceName = "ThisFieldIsRequired", ErrorMessageResourceType = typeof(Resource))]
        [RegularExpression(@"^[\w-]+(\.[\w-]+)*@([a-z0-9-]+(\.[a-z0-9-]+)*?\.[a-z]{2,6}|(\d{1,3}\.){3}\d{1,3})(:\d{4})?$", ErrorMessageResourceName = "ThisFieldIsRequired", ErrorMessageResourceType = typeof(Resource))]
        [Display(Name = "EmailID", ResourceType = typeof(Resource))]
        public string EmailID { get; set; }
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