列表 – 试图从Biopython获取分类信息

我试图改变以前的脚本,利用bio
python获取有关物种门的信息.编写此脚本是为了一次检索一个物种的信息.我想修改脚本,以便我可以一次为100个生物做这个.

这是初始代码

import sys
from Bio import Entrez

def get_tax_id(species):
    """to get data from ncbi taxomomy, we need to have the taxid.  we can
    get that by passing the species name to esearch, which will return
    the tax id"""
    species = species.replace(" ", "+").strip()
    search = Entrez.esearch(term = species, db = "taxonomy", retmode = "xml")
    record = Entrez.read(search)
    return record['IdList'][0]

def get_tax_data(taxid):
    """once we have the taxid, we can fetch the record"""
    search = Entrez.efetch(id = taxid, db = "taxonomy", retmode = "xml")
    return Entrez.read(search)

Entrez.email = ""
if not Entrez.email:
    print "you must add your email address"
    sys.exit(2)
taxid = get_tax_id("Erodium carvifolium")
data = get_tax_data(taxid)
lineage = {d['Rank']:d['ScientificName'] for d in 
    data[0]['LineageEx'] if d['Rank'] in ['family', 'order']}

我已设法修改脚本,以便它接受包含我正在使用的生物之一的本地文件.但我需要将其扩展到100种生物体.
所以我的想法是从我的生物体文件中生成一个列表,并以某种方式将列表中生成的每个项目分别输入到taxid = get_tax_id(“Erodium carvifolium”)中,并用我的生物名称替换“Erodium carvifolium”.但我不知道该怎么做.

以下是我的一些调整代码的示例版本

 import sys
from Bio import Entrez


def get_tax_id(species):
    """to get data from ncbi taxomomy, we need to have the taxid. we can
    get that by passing the species name to esearch, which will return
    the tax id"""
    species = species.replace(' ', "+").strip()
    search = Entrez.esearch(term = species, db = "taxonomy", retmode = "xml")
    record = Entrez.read(search)
    return record['IdList'][0]

def get_tax_data(taxid):
    """once we have the taxid, we can fetch the record"""
    search = Entrez.efetch(id = taxid, db = "taxonomy", retmode = "xml")
    return Entrez.read(search)

Entrez.email = ""
if not Entrez.email:
    print "you must add your email address"
    sys.exit(2)
list = ['Helicobacter pylori 26695', 'Thermotoga maritima MSB8', 'Deinococcus radiodurans R1', 'Treponema pallidum subsp. pallidum str. Nichols', 'Aquifex aeolicus VF5', 'Archaeoglobus fulgidus DSM 4304']
i = iter(list)
item = i.next()
for item in list:
     ???
taxid = get_tax_id(?)
data = get_tax_data(taxid)
lineage = {d['Rank']:d['ScientificName'] for d in
    data[0]['LineageEx'] if d['Rank'] in ['phylum']}
print lineage, taxid

问号指的是我难以接受的地方,下一步该做什么.我不知道如何连接我的循环来取代?在get_tax_id(?)中.或者我是否需要以某种方式附加列表中的每个项目,以便每次修改它们以包含get_tax_id(幽门螺杆菌26695),然后找到一些方法将它们放在包含taxid的行中=

最佳答案 这是你需要的,把它放在你的函数定义下面,即在以下行之后:sys.exit(2)

species_list = ['Helicobacter pylori 26695', 'Thermotoga maritima MSB8', 'Deinococcus radiodurans R1', 'Treponema pallidum subsp. pallidum str. Nichols', 'Aquifex aeolicus VF5', 'Archaeoglobus fulgidus DSM 4304']

taxid_list = [] # Initiate the lists to store the data to be parsed in
data_list = []
lineage_list = []

print('parsing taxonomic data...') # message declaring the parser has begun

for species in species_list:
    print ('\t'+species) # progress messages

    taxid = get_tax_id(species) # Apply your functions
    data = get_tax_data(taxid)
    lineage = {d['Rank']:d['ScientificName'] for d in data[0]['LineageEx'] if d['Rank'] in ['phylum']}

    taxid_list.append(taxid) # Append the data to lists already initiated
    data_list.append(data)
    lineage_list.append(lineage)

print('complete!')
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