我有一个搜索模型,构建一个基本上是原始SQL的字符串.此字符串通过find_by_sql调用运行,并在下面第5行返回到控制器(@ search.query< – query是返回find_by_sql结果的方法):
1 def roster_builder
2 authorize! :access_roster_builder, current_coach
3 @search = Search.new(sport: current_coach.primary_sport, conditions: params[:search])
4
5 @athletes = @search.query.page(params[:page]).per_page(8)
6
7 if params[:refresh]
8 render "athletes_refresh"
9 else
10 render "athletes" if request.format.js?
11 end
12 end
这会返回一个数组,但是我收到此错误:
NoMethodError (undefined method `page' for #<Array:0x00000105b7add0>)
所以我发现插入以下内容应该解决这个问题:
require 'will_paginate/array'
我已经尝试将它放在我的控制器中,并且will_paginate.rb初始化文件无效.我甚至对find_by_sql结果做了.to_a – 同样的错误.究竟是什么问题?我正在使用will_paginate 3.0.4版,因此它完全是最新的.在github上,它甚至说要求应该使这项工作正常:https://github.com/mislav/will_paginate/wiki/Backwards-incompatibility
最佳答案 看这篇文章:
https://github.com/mislav/will_paginate/issues/263
因此,对于您的控制器,它看起来像这样
def roster_builder
require 'will_paginate/array'
authorize! :access_roster_builder, current_coach
@search = Search.new(sport: current_coach.primary_sport, conditions: params[:search])
# @athletes = @search.query.page(params[:page]).per_page(8)
@athletes = @search.query.paginate page: params[:page], per_page: 8
if params[:refresh]
render "athletes_refresh"
else
render "athletes" if request.format.js?
end
end