java – 如何创建spring参数化事务测试

2019年8月4日 134次阅读

在我的测试中,我需要使用
spring依赖注入事务和参数.我找到了如何使用参数化和DI的示例：

@RunWith(value = Parameterized.class)
@ContextConfiguration(locations = { "classpath:applicationContextTest-business.xml" })
public class TournamentServiceTest {

@Autowired
TournamentService tournamentService;

    public TournamentServiceTest(int playerCount) {
        this.playerCount = playerCount;
    }

    @Parameters
    public static List<Object[]> data() {
        final List<Object[]> parametry = new ArrayList<Object[]>();
        parametry.add(new Object[] { 19 });
        parametry.add(new Object[] { 20 });
        return parametry;
    }

    @Before
    public void vytvorTurnaj() throws Exception {
        testContextManager = new TestContextManager(getClass());
        testContextManager.prepareTestInstance(this);
    }

@Test
public void test1() {
     Assert.assertFalse(false);
}

}

这个例子有效.现在我需要向这个类添加事务：

@RunWith(value = Parameterized.class)
@ContextConfiguration(locations = { "classpath:applicationContextTest-business.xml" })
@Transactional
@TransactionConfiguration(defaultRollback = true)
public class TournamentServiceTest ...

当我添加这两个新行然后这个测试抛出异常：

org.springframework.aop.framework.AopConfigException: Could not generate CGLIB subclass of class [class org.toursys.processor.service.TournamentServiceTest]: Common causes of this problem include using a final class or a non-visible class; nested exception is java.lang.IllegalArgumentException: Superclass has no null constructors but no arguments were given

因为他想添加空构造函数：

public TournamentServiceTest() {
    this.playerCount = 20;
}

但我不能添加这个,因为然后参数化不能运行此测试.我怎么能解决这个问题？

最佳答案 Spring TestContext Framework目前执行
not support Parameterized tests.您需要一个自定义规则或运行器.有空位

pull request,您可以从那里获取代码.

从0700春季开始,您可以使用

@ClassRule
public static final SpringClassRule SPRING_CLASS_RULE = new SpringClassRule();

@Rule
public final SpringMethodRule springMethodRule = new SpringMethodRule();
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