Python：matplotlib – 黑白分散

2023年10月13日 272次阅读

我觉得我在这里遗漏了一些非常明显的东西,但我无法在pylab中得到散点图以黑白打印.任何和所有的帮助将不胜感激.这是我的代码：

from pylab import *
from random import random
ioff()

r = range(10)
x = [3 + i + random() for i in r]
y = [50*i + random() for i in r]
x2 = [5 + i + random() for i in r]
y2 = [5*i + random() for i in r]

scatter(x,y, marker = 'o', hold = True, label = 'collected underwear',cmap=cm.Greys)
scatter(x2,y2, marker = 's', hold = True, label = 'Profit!',cmap=cm.Greys)
legend(loc='upper left')

show()

谢谢,

亚当

最佳答案 如果您只想随意指定颜色,请执行

color="k"

黑色,做

color="0.x"

对于灰度,x可以是任何数字,只要0.x在0和1之间.

但是,如果您希望标记颜色由另一个数组z确定,请执行

scatter(x,y,c=z, cmap=cm.Greys)

因此对于

from pylab import *
from random import random
r = range(10)
x = [3 + i + random() for i in r]
y = [50*i + random() for i in r]
x2 = [5 + i + random() for i in r]
y2 = [5*i + random() for i in r]
z2 = [i + random() for i in r]
scatter(x,y,   c="0.1", marker = 'o', hold = True, label = 'collected underwear')
scatter(x2,y2, c=z2,marker = 's',  hold = True, label = 'Profit!',cmap=cm.Greys)
legend(loc='upper left')
show()

你将会有

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