假设我有一个班级:
class Cat:
def __init__(self, name = "default", age = 0):
self.name = name
self.age = age
我还有一个猫列表:
l = [Cat('Joe')]
现在我不能打电话给以下人员:
if 'Joe' in l: # the right syntax would be if Cat('Joe') in list
我需要重载哪个运算符才能通过其成员变量名识别类Cat的对象?
最佳答案 您必须定义__eq__方法,如下所示:
class Cat:
def __init__(self, name = "default", age = 0):
self.name = name
self.age = age
def __eq__(self, other):
if isinstance(other, str):
return self.name == other
elif isinstance(other, Cat):
return self.name == other.name
这样当你运行支票时:
l = [Cat('Joe')]
'Joe' in l
#True