如何从部件列表构建URL路径?

这样做:

from urllib.parse import urljoin
urljoin('https://site/folder', 'page')

返回https:// site / page.然后就可以了,我可以追加一个/.但是当我的变量已经/和我追加另一个时,我得到了双杠:

urljoin('https://site/folder//', 'page')
>>> 'https://site/folder//page'

在加入网址时,urljoin允许这个双杠//不会错!

如何加入这样的URL部分列表:

urljoin('https://site/folder', 'page', 'otherpage' )
> https://site/folder/page/otherpage

urljoin('https://site/folder', 'page', 'otherpage.jsf' )
> https://site/folder/page/otherpage.jsf

urljoin('https://site/folder/' , 'page.htm', )
> https://site/folder/page.htm

urljoin('https://site/folder//', '/page', '///otherpage' )
> https://site/folder/page/otherpage

urljoin('https://site/folder//', '//page/',  '//otherpage.php'  )
> https://site/folder/page/otherpage.php

urljoin('https://site/folder//', 'page', '/otherpage////' )
> https://site/folder/page/otherpage

最佳答案 我确信有不同的方法可以做到这一点

from urllib.parse import urljoin
from functools import reduce # python3

def clean_url(url):
    return url.strip('/') + '/'

def joinurllist(urls):
    return reduce(urljoin, map(clean_url, urls))

joinurllist(['https://site/folder//', 'page', '///otherpage/'])
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