java – 具有相同@RequestMapping的Spring MVC多个控制器

2019年8月3日 171次阅读

我正在尝试制作一个允许用户从登录页面index.htm登录的Web应用程序.此操作与LoginController映射,登录成功后,用户将用户返回到相同的index.htm,但登录用户并使用欢迎消息迎接用户.

index.htm还有另一个名为itemform的表单,它允许用户将项目名称添加为文本.此操作由itemController控制.

我的问题是我的LoginController和itemController都有相同的@RequestMapping,因此我收到此错误：

Error creating bean with name ‘org.springframework.web.servlet.mvc.annotation.DefaultAnnotationHandlerMapping#0′ defined in ServletContext resource [/WEB-INF/tinga-servlet.xml]: Initialization of bean failed; nested exception is java.lang.IllegalStateException: Cannot map handler [loginController] to URL path [/index.htm]: There is already handler [com.tinga.LoginController@bf5555] mapped.

Cannot map handler [loginController] to URL path [/index.htm]: There is already handler [com.tinga.LoginController@bf5555] mapped.

我该如何解决这个问题？

最佳答案

@RequestMapping(value="/login.htm")
public ModelAndView login(HttpServletRequest request, HttpServletResponse response) {
   // show login page if no parameters given
   // process login if parameters are given
}

@RequestMapping(value="/index.htm")
public ModelAndView index(HttpServletRequest request, HttpServletResponse response) {
   // show the index page
}

最后,您需要一个servlet过滤器来拦截请求,如果您没有请求login.htm页面,则必须检查以确保用户已登录.如果您,则允许过滤链继续.如果没有,请向/login.htm发出转发

public class LoginFilter implements Filter {
  public void doFilter(ServletRequest request,  ServletResponse response, FilterChain chain)
            throws IOException, ServletException {

    HttpServletRequest httpServletRequest = (HttpServletRequest)request;

    boolean loggedIn = ...; // determine if the user is logged in.
    boolean isLoginPage = ...; // use path to see if it's the login page

    if (loggedIn || isLoginPage) {
        chain.doFilter(request, response);
    }
    else {
        request.getRequestDispatcher("/login.htm").forward(request, response);
    }
  }
}

并在web.xml中

我的部署描述符示例：

<filter>
    <filter-name>LoginFilter</filter-name>
    <filter-class>LoginFilter</filter-class>
</filter>

<filter-mapping>
    <filter-name>LoginFilter</filter-name>
    <url-pattern>/*</url-pattern>
    <dispatcher>REQUEST</dispatcher>  
    <dispatcher>FORWARD</dispatcher> 
</filter-mapping>

这完全来自记忆,但它应该让你了解如何解决这个问题.

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