ios – 在长按手势的UIButton中显示图像

2019年8月3日 307次阅读

我有以下问题.我有一个UIScrollView,我有几个按钮,图标设置为这些按钮上的图像.我有一个长按识别器连接到每个按钮.如何在长按手势上的发件人按钮上显示较小的删除图标？我的目标是创建当用户想要删除特定应用程序时由iOS呈现的行为.

这是按钮的代码(带图像)：

//set the button with the image of conference here.
UIButton * button = [UIButton buttonWithType:UIButtonTypeCustom];
button.frame = CGRectMake(3, 3, w-5, h-5);
CALayer * l = [button layer];
[l setMasksToBounds:YES];
[l setCornerRadius:8.0];
[button setImage:thumb forState:UIControlStateNormal];

button.property = confInfo;
[button addTarget:self action:@selector(buttonClicked:) forControlEvents:UIControlEventTouchUpInside];
button.tag = i; 
bView.tag = i;

//Add gesture recognizer to be used for deletion of conference.
UILongPressGestureRecognizer *pahGestureRecognizer = [[UILongPressGestureRecognizer alloc] initWithTarget:self action:@selector(longPressGestureRecognizerStateChanged:)];

pahGestureRecognizer.minimumPressDuration = 1.0;
[button addGestureRecognizer:pahGestureRecognizer];

此代码处于循环中(请参阅代码中的i).我的长时间动作是这样的：

- (void)longPressGestureRecognizerStateChanged:(UIGestureRecognizer *)gestureRecognizer {

      switch (gestureRecognizer.state) {

          case UIGestureRecognizerStateEnded:
               NSLog(@"Tapped!!!");                    
               break;

          default:
               break;
      }
 }

如何通过我点击此操作的按钮来显示按钮右上角的较小X图像？

最佳答案 您的手势识别器应通过其视图属性附加到UIButton.

case UIGestureRecognizerStateEnded:
    NSLog(@"Tapped!!!");
    [((UIButton*)gestureRecognizer.view) setImage:thumbWithX forState:UIControlStateNormal];
    break;
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