问候,
这是一个相当明确的问题.
我必须使用< java>启动一个java作业,它将与ant并行运行,如果作业比ant进程更长,则可以,因此spawn =“true”.
我必须在指定的文件中看到作业输出.对于spawn =“false”,这可以通过output =“job.out”完全实现,但是我有点运气产生“= true”.
那么,有没有任何适度的黑客攻击或我真的必须用下面的exec包装java调用?
CMD /C my-java-command-and-hardcoded-classpath-goes-here > job.out
谢谢,
安东
最佳答案
import java.io.FileNotFoundException;
import java.io.FileOutputStream;
import java.io.PrintStream;
import java.lang.reflect.InvocationTargetException;
import java.util.Arrays;
public class StreamRedirector {
public static void main(String[] args) throws FileNotFoundException, ClassNotFoundException,
NoSuchMethodException, InvocationTargetException, IllegalAccessException {
System.out.println(Arrays.toString(args));
// parse the arguments
if (args.length != 2) {
throw new IllegalArgumentException(
"Usage:" +
"\targ0 = wrapped main FQN;\n" +
"\targ1 = dest output file name;\n" +
"\tother args are passed to wrapped main;"
);
}
String mainClass = args[0];
String destinationFile = args[1];
// redirect the streams
PrintStream outErr = new PrintStream(new FileOutputStream(destinationFile));
System.setErr(outErr);
System.setOut(outErr);
// delegate to the other main
String[] wrappedArgs = new String[args.length - 2];
System.arraycopy(args, 2, wrappedArgs, 0, wrappedArgs.length);
Class.forName(mainClass).getMethod("main", String[].class).invoke(null, (Object) wrappedArgs);
}
}