我正在开发一个扑动的应用程序,并认识到状态管理的意外行为.我创建了一个示例应用程序来重现行为,您可以在下面找到代码和日志输出.
该应用程序包含一个简单的ListView,其中包含10个有状态容器(文本装饰).
当我向下滚动时,每个容器及其容器状态将按预期创建一次.当我再次向上滚动时,Flutter会为显示屏上再次出现的每个容器小部件重新创建每个状态(但不是容器小部件).
我希望颤振会在没有重新创建整个状态对象的情况下检索先前的状态.
我在这里做错了吗?
class MyHomePage extends StatefulWidget {
MyHomePage({Key key}) : super(key: key) {
print("MyHomePage constructor");
}
@override
_MyHomePageState createState() {
print("createState");
return _MyHomePageState();
}
}
class _MyHomePageState extends State<MyHomePage> {
_MyHomePageState() {
print("_MyHomePageState contructor");
}
void initState() {
super.initState();
print("_MyHomePageState initState");
}
@override
Widget build(BuildContext context) {
return Scaffold(
body: ListView.builder(
itemBuilder: (context, index) {
return ContainerWidget(index, key: ValueKey(index));
},
itemCount: 10,
));
}
}
class ContainerWidget extends StatefulWidget {
int index;
ContainerWidget(this.index, {key}) : super(key: key) {
print("ContainerWidget constructor for index $index");
}
@override
State<StatefulWidget> createState() {
print("ContainerWidget createState for index $index");
return _ContainerState();
}
}
class _ContainerState extends State<ContainerWidget> {
_ContainerState() {
print("_ContainerState constructor");
}
void initState() {
super.initState();
print("_ContainerState initState for index ${widget.index}");
}
@override
Widget build(BuildContext context) {
return Container(
child: Center(
child: Text("Index: ${widget.index}"),
),
height: 200,
decoration: BoxDecoration(
border: Border(
bottom: BorderSide(color: Colors.green),
),
),
);
}
}
对数输出:
I/flutter (22400): createState
I/flutter (22400): _MyHomePageState contructor
I/flutter (22400): _MyHomePageState initState
I/flutter (22400): ContainerWidget constructor for index 0
I/flutter (22400): ContainerWidget createState for index 0
I/flutter (22400): _ContainerState constructor
I/flutter (22400): _ContainerState initState for index 0
I/flutter (22400): ContainerWidget constructor for index 1
I/flutter (22400): ContainerWidget createState for index 1
I/flutter (22400): _ContainerState constructor
I/flutter (22400): _ContainerState initState for index 1
I/flutter (22400): ContainerWidget constructor for index 2
I/flutter (22400): ContainerWidget createState for index 2
I/flutter (22400): _ContainerState constructor
I/flutter (22400): _ContainerState initState for index 2
I/flutter (22400): ContainerWidget constructor for index 3
I/flutter (22400): ContainerWidget createState for index 3
I/flutter (22400): _ContainerState constructor
I/flutter (22400): _ContainerState initState for index 3
I/flutter (22400): ContainerWidget constructor for index 4
I/flutter (22400): ContainerWidget createState for index 4
I/flutter (22400): _ContainerState constructor
I/flutter (22400): _ContainerState initState for index 4
I/flutter (22400): ContainerWidget constructor for index 5
I/flutter (22400): ContainerWidget createState for index 5
I/flutter (22400): _ContainerState constructor
I/flutter (22400): _ContainerState initState for index 5
I/flutter (22400): ContainerWidget createState for index 1
I/flutter (22400): _ContainerState constructor
I/flutter (22400): _ContainerState initState for index 1
I/flutter (22400): ContainerWidget createState for index 0
I/flutter (22400): _ContainerState constructor
I/flutter (22400): _ContainerState initState for index 0
最佳答案 这是预期的,因为这些项目在离开屏幕时会被卸载.
如果你不想那样,你会想要使用我们称之为“保持活力”的东西.
你可以通过在你的State类中添加一个mixin来实现:
class _MyHomePageState extends State<MyHomePage> with AutomaticKeepAliveClientMixin {
bool get wantKeepAlive => true;
// ...
}