sql – SUM 3个不同的“CASE”列,有三个不同的总计

2023年11月5日 183次阅读

我是新手,所以如果我问这个问题是对的,我很抱歉.但是我试图从我的表中获得4种不同的SUM,它使用了4种不同的情况.但我希望id只能与总数一起列出一次.我会告诉你我拥有什么,以及我想要得到什么.请尽可能帮助.

    SELECT schools.name, articles.competition_place,

    Case when articles.competition = 'yes' and competition_place = '1' then int '100'
       when articles.competition = 'yes' and competition_place = '2' then int '60'
       when articles.competition = 'yes' and competition_place = '3' then int '20'
    ELSE 0 end AS "Competition_Score",

    Case when articles.out_reach = 'yes' then int '30'
        ELSE 0 end AS "out_reach_Score",

    CASE when schools.school_id is not null then int '5'
        ELSE 0 end as "article_score",

    (Case when articles.competition = 'yes' and competition_place = '1' then int '100'
        when articles.competition = 'yes' and competition_place = '2' then int '60'
        when articles.competition = 'yes' and competition_place = '3' then int '20'
        ELSE 0 end) +
    (Case when articles.out_reach = 'yes' then int '30'
        ELSE 0 end) +
    (CASE when schools.school_id is not null then int '5'
        ELSE 0 end) as "total_score"
    from articles
    join clubs on articles.club_id = clubs.club_id
    join schools on clubs.school_id = schools.school_id

My table that I have

这就是我想要的.

This is the table I’m trying to get

这可能吗？

最佳答案 使用聚合和分组

SELECT schools.name, articles.competition_place,

sum(Case when articles.competition = 'yes' and competition_place = '1' then int '100'
   when articles.competition = 'yes' and competition_place = '2' then int '60'
   when articles.competition = 'yes' and competition_place = '3' then int '20'
ELSE 0 end) AS "Competition_Score",

sum(Case when articles.out_reach = 'yes' then int '30'
    ELSE 0 end) AS "out_reach_Score",

sum(CASE when schools.school_id is not null then int '5'
    ELSE 0 end) as "article_score",

sum((Case when articles.competition = 'yes' and competition_place = '1' then int '100'
    when articles.competition = 'yes' and competition_place = '2' then int '60'
    when articles.competition = 'yes' and competition_place = '3' then int '20'
    ELSE 0 end)) +
sum((Case when articles.out_reach = 'yes' then int '30'
    ELSE 0 end)) +
sum(CASE when schools.school_id is not null then int '5'
    ELSE 0 end)) as "total_score"
from articles
join clubs on articles.club_id = clubs.club_id
join schools on clubs.school_id = schools.school_id
group by schools.name, articles.competition_place
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