我正在使用Twill检索包含所需.txt数据的页面,以便将它们存储为Excel文件.数据受密码保护,因此我从/ user / login页面登录.
我的代码遇到了这样的问题:它尝试从登录屏幕访问文本页面并打到HTML的砖墙而不是.txt本身.
当我运行登录时:
path = "https://naturalgasintel.com/ext/resources/Data-Feed/Daily-GPI/"
end = "td.txt"
go("http://www.naturalgasintel.com/user/login")
showforms()
fv("2", "user[email]", user_email)
fv("2", "user[password]", user_password)
fv("2", "commit", "Login")
datafilelocation = path + year + "/" + month + "/" + date + end
go(datafilelocation)
当我的代码转到(datafilelocation)时,我得到了这个:
==> at https://www.naturalgasintel.com/user/login?referer=%2Fext%2Fresources%2FData-Feed%2FDaily-GPI%2F2018%2F12%2F20181221td.txt
Out[18]: u'https://www.naturalgasintel.com/user/login?referer=%2Fext%2Fresources%2FData-Feed%2FDaily-GPI%2F2018%2F12%2F20181221td.txt'
因此,当我真正想要访问该页面时,它指向引用者而不是实际文本:
https://naturalgasintel.com/ext/resources/Data-Feed/Daily-GPI/2018/12/20181221td.txt
我使用fv(“2”,“commit”,“Login”)而不是submit()的原因是当我到达页面时它给了我这个:
showforms()
Form name=quick-search (#1)
## ## __Name__________________ __Type___ __ID________ __Value__________________
1 q text q Search
Form #2
## ## __Name__________________ __Type___ __ID________ __Value__________________
1 utf8 hidden (None) ✓
2 authenticity_token hidden (None) pnFnPGhMomX2Lyh7/U8iGOZKsiQnyicj7BWT ...
3 referer hidden (None) https://www.naturalgasintel.com/ext/ ...
4 popup hidden (None) false
5 user[email] text user_email
6 user[password] password user_pas ...
7 user[remember_me] hidden (None) 0
8 user[remember_me] checkbox user_rem ... None
9 commit submit (None) Login
然后它在我提交()之后告诉我:
Note: submit is using submit button: name="commit", value="Login"
解决这个问题的最佳解决方案是什么?
最佳答案 如果您使用Mechanize而不是Twill可以,请提供以下内容:
import mechanize
username = ""
password = ""
login_post_url = "http://www.naturalgasintel.com/user/login"
internal_url = "https://naturalgasintel.com/ext/resources/Data-Feed/Daily-GPI/2018/12/20181221td.txt"
browser = mechanize.Browser()
browser.open(login_post_url)
browser.select_form(nr = 1)
browser.form['user[email]'] = username
browser.form['user[password]'] = password
browser.submit()
response = browser.open(internal_url)
print response.read()