如何使用SQL查询优化我的代码
$collection->filter(function ($item) use ($i) {
return $item->created_at->month == $i->month;
})->count();
我希望代替集合上的过滤器函数在sql中进行过滤,以便它可以更快
这是功能:
$data = [];
switch ($range) {
//monthly
case self::$timeRanges[0]:
for ($i = Carbon::now()->copy()->subYear()->endOfMonth(); $i <= Carbon::now()->subMonth()->endOfMonth(); $i->addMonths(1)) {
$data[$i->month] = $collection->filter(function ($item) use ($i) {
return $item->created_at->month == $i->month;
})->count();
}
break;
//weekly
case self::$timeRanges[1]:
$collection = $collection->where('created_at', '>=', Carbon::now()->subWeek()->endOfWeek()->subWeeks(5))->where('created_at', '<=', Carbon::now()->subWeek()->endOfWeek());
for ($i = Carbon::now()->copy()->subWeek()->endOfWeek()->subWeeks(5); $i <= Carbon::now()->copy()->subWeek()->endOfWeek(); $i->addWeeks(1)) {
$data[$i->weekOfMonth] = $collection->filter(function ($item) use ($i) {
return $item->created_at->weekOfYear == $i->weekOfYear;
})->count();
}
break;
}
return ($data);
感谢您的帮助,祝您度过愉快的一天!
最佳答案 只是为了扩展@ Elie的答案,你甚至不需要使用原始查询. Laravel非常适合日期条件,在
Queries页面上有很好的记录.
$desiredMonth = 12;
Model::whereMonth('created_at', $desiredMonth)->get();
但是,这并不能完全回答手头的问题.我们需要做的是检索所有相关结果,然后按月过滤检索到的结果.我相信通过从SQL检索所有结果然后按原样对它们进行过滤来实现这一目标会更有效,更快,但迭代代码更少:
$collection = Model::whereYear(2018)->get();
$months = $collection->groupBy(function ($item, $key) {
return $item->created_at->month;
});
$months->toArray();
[
'1' => [[...],[...],[...]],
'2' => [[...],[...],[...]],
'3' => [[...],[...],[...]],
'4' => [[...],[...],[...]],
'5' => [[...],[...],[...]],
'6' => [[...],[...],[...]],
'7' => [[...],[...],[...]],
'8' => [[...],[...],[...]],
'9' => [[...],[...],[...]],
'10' => [[...],[...],[...]],
'11' => [[...],[...],[...]],
'12' => [[...],[...],[...]],
]
此外,如果您坚持使用SQL进行过滤,则可以执行groupBy:
Model::groupBy(\DB::raw('MONTH(created_at) as month'))->get();
您需要自己进行测试,以确定哪种更快或最有效.此外,一些数据库不允许多个分组(我们在这里没有,但您可能想要添加)而不修改其配置,因此除非您使用大量数据集,否则我的个人头奖将是原始方法.