删除python中字典值的重复项

2024年2月1日 330次阅读

对不起主题的标题含糊不清,我觉得很难解释.

我有一个字典,其中每个值都是一个项目列表.我希望删除重复的项目,以便每个项目在列表中显示最少时间(最好是一次).

考虑字典：

example_dictionary = {"weapon1":[1,2,3],"weapon2":[2,3],"weapon3":[2,3]}

‘weapon2’和’weapon3’具有相同的值,因此它应该导致：

result_dictionary = {"weapon1":[1],"weapon2":[3],"weapon3":[2]}

因为我不介意订单,它也可能导致：

result_dictionary = {"weapon1":[1],"weapon2":[2],"weapon3":[3]}

但是当“没有选择”时,它应该留下价值.考虑这个新词典：

example_dictionary = {"weapon1":[1,2,3],"weapon2":[2,3],"weapon3":[2,3],"weapon4":[3]}

现在,因为它只能在不将键留空的情况下分配“2”或“3”,所以可能的输出是：

result_dictionary = {"weapon1":[1],"weapon2":[3],"weapon3":[2],"weapon4":[3]}

我可以将问题放到第一部分并进行管理,但我更喜欢将这两个部分放在一起解决

最佳答案

#!/usr/bin/env python3

example_dictionary = {"weapon1":[1,2,3],"weapon2":[2,3],"weapon3":[2,3]}

result = {}
used_values = []

def extract_semi_unique_value(my_list):
    for val in my_list:
        if val not in used_values:
            used_values.append(val)
            return val
    return my_list[0]

for key, value in example_dictionary.items():
    semi_unique_value = extract_semi_unique_value(value)
    result[key] = [semi_unique_value]

print(result)
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