我在
python中编写了一个scraper来从网页上获取不同的类别名称,但它无法从该页面获取任何内容.我很困惑,不能弄清楚我哪里出错了.任何帮助将非常感激.
以下是该网页的链接:URL
这是我到目前为止所尝试的:
from bs4 import BeautifulSoup
import requests
res = requests.get("replace_with_above_url",headers={"User-Agent":"Mozilla/5.0"})
soup = BeautifulSoup(res.text,"lxml")
for items in soup.select('.slide_container .h3.standardTitle'):
print(items.text)
我所追求的一个类别名称的元素:
<div class="slide_container">
<a href="/offers/furniture/" tabindex="0">
<picture style="float: left; width: 100%;"><img style="width:100%" src="/_m4/9/8/1513184943_4413.jpg" data-w="270"></picture>
<div class="floated-details inverted" style="height: 69px;">
<div class="h3 margin-top-sm margin-bottom-sm standardTitle">
Furniture Offers #This is the name I'm after
</div>
<p class="carouselDesc">
</p>
</div>
</a>
</div>
最佳答案
from bs4 import BeautifulSoup
import requests
headers = {
'accept':'text/html,application/xhtml+xml,application/xml;q=0.9,image/webp,image/apng,*/*;q=0.8',
'accept-encoding':'gzip, deflate, br',
'accept-language':'en-US,en;q=0.9',
'cache-control':'max-age=0',
'referer':'https://www.therange.co.uk/',
'upgrade-insecure-requests':'1',
'user-agent':'Mozilla/5.0 (Macintosh; Intel Mac OS X 10_13_1) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/63.0.3239.84 Safari/537.36',
}
res = requests.get("https://www.therange.co.uk/",headers=headers)
soup = BeautifulSoup(res.text,'html.parser')
for items in soup.select('.slide_container .h3.standardTitle'):
print(items.text)
试试这个
a user-agent is not enough because headers are the most important part
of scrapping.if you miss any header then server ll treat you as a bot.