go – 如何在客户端断开连接时正确使用ctx.Done()?

如果客户端将因网络错误而断开连接,则服务器必须在我的情况下关闭pub / sub连接.我知道ctx.Done()函数,但在我的情况下不知道如何正确使用它.有人可以解释一下吗?

grpc-go:1.7.0

去版本go1.8.4

func (a *API) Notifications(in *empty.Empty, stream pb.Service_NotificationsServer) error {
    ctx := stream.Context()
    _, ok := user.FromContext(ctx)
    if !ok {
        return grpc.Errorf(codes.Unauthenticated, "user not found")
    }

    pubsub := a.redisClient.Subscribe("notifications")
    defer pubsub.Close()

    for {
        msg, err := pubsub.ReceiveMessage()
        if err != nil {
            grpclog.Warningf("Notifications: pubsub error: %v", err)
            return grpc.Errorf(codes.Internal, "pubsub error %v", err)
        }

        notification := &pb.Notification{}
        err = json.Unmarshal([]byte(msg.Payload), notification)
        if err != nil {
            grpclog.Warningf("Notifications: parse error: %v", err)
            continue
        }
        if err := stream.Send(notification); err != nil {
            grpclog.Warningf("Notifications: %v", err)
            return err
        }
        grpclog.Infof("Notifications: send msg %v", notification)
    }
}

最佳答案 你可以使用select.而不是正常从函数获取数据,使用通道获取数据和go例程来处理它.

有点像这样:

func (a *API) Notifications(in *empty.Empty, stream 
    pb.Service_NotificationsServer) error {
    ctx := stream.Context()
    _, ok := user.FromContext(ctx)
    if !ok {
        return grpc.Errorf(codes.Unauthenticated, "user not found")
    }

    pubsub := a.redisClient.Subscribe("notifications")
    defer pubsub.Close()

    // I can not build the code, so I assume the msg in your code Message struct
    c := make(chan Message)
    go func() {
        for {
            msg, err := pubsub.ReceiveMessage()
            if err != nil {
                grpclog.Warningf("Notifications: pubsub error: %v", err)
                close(c)
                return grpc.Errorf(codes.Internal, "pubsub error %v", err)
            }
            c<- msg
        }
    }()

    for {
        select {
            case msg, ok  := <-c:
                if !ok {
                    // channel is closed handle it
                }
                notification := &pb.Notification{}
                err = json.Unmarshal([]byte(msg.Payload), notification)
                if err != nil {
                    grpclog.Warningf("Notifications: parse error: %v", err)
                    continue
                }
                if err := stream.Send(notification); err != nil {
                    grpclog.Warningf("Notifications: %v", err)
                    return err
                }
                grpclog.Infof("Notifications: send msg %v", notification)
            case <- ctx.Done():
                // do exit logic. some how close the pubsub, so next 
                // ReceiveMessage() return an error
                // if forget to do that the go routine runs for ever 
                // until the end of main(), which I think its not what you wanted
                pubsub.Close() // Its just pseudo code
                return
        }
    }
}

从通道中读取消息(我假设类型为Message),并使用select的电源.

在这种情况下另外两个相关的事情:

>确保完成此功能后,go例程结束.我无法猜测,因为我不知道代码,但我假设有一个Close()方法关闭pubsub所以下一个ReceiveMessage返回错误. (我看到推迟做我希望的工作)
>如果在ctx.Done之前ReceiveMessage中存在错误,您可以关闭通道然后中断循环.

点赞