我一直在反复编程,我在学习如何使用fork()以便递归生成子进程时遇到了麻烦.我开始编写一些非常复杂的东西,我决定以更简单的方式重新开始.
我刚开始学习流程,但我很难理解它们.
该程序旨在分叉一个进程树,但是,我必须从根分叉两个进程,在左侧3个子进程,在右侧有4个子进程.这些进程必须分别对自己的进程分别为3和4.
我的问题是程序可以分叉进程,但是每一方只有一个进程正在为各自的所有子进程做父母.
你能给我的任何帮助都会很棒,请告诉我,如果我不够清楚的话.
#include <unistd.h>
#include <stdio.h>
#include <fcntl.h>
#include <stdlib.h>
#include <sys/wait.h>
#include <sys/types.h>
/* Prototypes */
void three_children();
void four_children();
int main()
{
pid_t process;
int status,n;
printf("Number of levels: \n");
scanf("%d", &n);
for (int i = 0; i < n ; i++) {
process = fork();
switch (process) {
case -1:
printf("Error\n");
break;
case 0:
if (i == 0) {
printf("Left\n");
three_children(process, status);
}
if (i == 1) {
printf("Right\n");
three_children(process, status);
}
printf("Hi I'm a child PID: %d, my father is PPID: %d\n", getpid(), getppid());
exit(0);
default:
printf("I'm a father PPID: %d\n", getppid());
break;
}
}
}
void four_children(pid_t process, int status)
{
for (int j = 0; j < 4; j++) {
process = fork();
switch (process) {
case -1:
printf("Error\n");
break;
case 0:
printf("I'm child: %d, and my father is: %d\n(four children)\n", getpid(), getppid());
exit(0);
break;
default:
printf("I'm a father process: %d\n", getpid());
four_children(process, status);
for (int j = 0; j < 3; j++) {
wait(&status);
}
break;
}
}
}
void three_children(pid_t process, int status)
{
for (int k = 0; k < 3; k++) {
process = fork();
switch (process) {
case -1:
printf("Error\n");
break;
case 0:
printf("I'm a child: %d, and my father is: %d\n(three children )\n", getpid(), getppid());
exit(0);
break;
default:
printf("I'm father %d\n", getpid());
three_child(process, status);
for (int j = 0; j < 3; j++) {
wait(&status);
}
break;
}
}
}
最佳答案
#include <stdlib.h>
#include <unistd.h>
#include <stdio.h>
typedef struct Node
{
int childrenCount;
struct Node* child[0];
} Node;
Node* makeNode(int children)
{
Node* result = (Node*)malloc(sizeof(Node) + sizeof(Node*) * children);
if (!result) {
exit(1);
}
result->childrenCount = children;
for(int loop = 0;loop < children; ++loop) {
result->child[loop] = NULL;
}
return result;
}
void buildTree(int indent, pid_t parent, Node* node);
void createChild(int indent, pid_t parent, Node* node, int childIndex)
{
pid_t pid = fork();
if (pid == -1) {
exit(1);
}
if (pid == 0) {
buildTree(indent + 1, getpid(), node->child[childIndex]);
srand(parent * 10 + childIndex);
exit(rand());
}
for(int ind = 0; ind < indent; ++ind) {
fprintf(stderr, " ");
}
fprintf(stderr, "Parent: %d Spawned %d\n", parent, pid);
}
void buildTree(int indent, pid_t parent, Node* node)
{
for(int ind = 0; ind < indent; ++ind) {
fprintf(stderr, " ");
}
fprintf(stderr, "Parent %d Has %d Children\n", parent, node->childrenCount);
for(int loop = 0; loop < node->childrenCount; ++loop) {
createChild(indent, parent, node, loop);
}
for(int loop = 0; loop < node->childrenCount; ++loop) {
int status;
int child = wait(&status);
for(int ind = 0; ind < indent; ++ind) {
fprintf(stderr, " ");
}
fprintf(stderr, "Parent: %d Reaped %d with status %d\n", parent, child, status);
}
}
int main()
{
Node* root = makeNode(2);
root->child[0] = makeNode(3);
for(int loopChild = 0;loopChild < 3; ++loopChild) {
root->child[0]->child[loopChild] = makeNode(3);
for(int loopGrandChild = 0;loopGrandChild < 3; ++loopGrandChild) {
root->child[0]->child[loopChild]->child[loopGrandChild] = makeNode(0);
}
}
root->child[1] = makeNode(4);
for(int loopChild = 0;loopChild < 4; ++loopChild) {
root->child[1]->child[loopChild] = makeNode(4);
for(int loopGrandChild = 0;loopGrandChild < 4; ++loopGrandChild) {
root->child[1]->child[loopChild]->child[loopGrandChild] = makeNode(0);
}
}
fprintf(stderr, "Start\n");
buildTree(0, getpid(), root);
fprintf(stderr, "Stop\n");
}