如何在QWebPage之前从特定URL读取QNetworkReply响应中的数据?但是当发出
finished()
信号时,QWebPage已经读取了回复,因此连接
readyRead()
或调用reply-> readAll()不返回任何内容.我尝试在我自己的QWebPage类中重载acceptNavigationRequest()方法,如下所示:
bool webPage::acceptNavigationRequest(QWebFrame *frame, const QNetworkRequest &request, QWebPage::NavigationType type)
{
//qDebug() << "filename = " << request.rawHeader("content-disposition");
if(request.url().path() == QStringLiteral("download.php"))
{
QNetworkReply *reply = networkAccessManager()->get(request);
QFile file;
file.setFileName(filename);
if(!file.open(QIODevice::ReadWrite))
{
/* handle error */
}
file.write(reply->readAll());
file.close();
return false;
}
但我无法回复工作…返回的回复无效(甚至不返回http状态代码,我知道这意味着发送的http请求无效但我不知道为什么).
欢迎采用不同的方法来解决这个问题!
最佳答案 使用带有lambda表达式的成品槽,您可以这样做: –
QNetworkReply* reply = networkAccessManager()->get(request);
connect(reply, &QNetworkReply::finished, [=]() {
if(reply->error() == QNetworkReply::NoError)
{
QByteArray response = reply->readAll();
// do something with the data...
}
else // handle error
{
qDebug(pReply->errorString());
}
});