如何执行XSL以从xml标记中删除文本

2019年7月28日 214次阅读

我有一个
XML：

<?xml version="1.0" encoding="UTF-8"?>
<COLLECTION>
<Added>
<part>
<weight>5kg</weight>

</part>
<part>
<weight></weight>
</part>
<part>
<weight>2kg</weight>
</part>
</Added>
<Update>
<part>
<weight></weight>
</part>
<part>
<weight>3kg</weight>
</part>
<part>
<weight>2kg</weight>
</part>
</Update>
</COLLECTION>

我想在它上面应用XSL,以便< weight>标签需要转换为权重并考虑唯一的数字.这样我想添加一些额外的标签,这在输入XML中不存在.< unitWeights>如果< weight>的值只是预定,然后它会显示KG休息它将是空白的.

预期产量：

<?xml version="1.0" encoding="UTF-8"?>
<COLLECTION>
<Added>
<part>
<Weight>5</Weight>
<unitWeights>KG</unitWeights>
</part>
<part>
<Weight></Weight>
<unitWeights></unitWeights>
</part>
<part>
<Weight>2</Weight>
<unitWeights>KG</unitWeights>
</part>
</Added>
<Update>
<part>
<Weight></Weight>
<unitWeights></unitWeights>
</part>
<part>
<Weight>3</Weight>
<unitWeights>KG</unitWeights>
</part>
<part>
<Weight>2</Weight>
<unitWeights>KG</unitWeights>
</part>
</Update>
</COLLECTION>

为此我申请了：

    <xsl:template match="Weight">
    <weight>
      <xsl:value-of select="translate(.,translate(., '0123456789', ''), '')"/>
    </weight>
  </xsl:template>
  <xsl:template match="WeightUnits">
    <unitWeights>KG</unitWeights>
    </xsl:template>

请帮我解决我错的地方.

最佳答案

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

  <xsl:template match="@*|node()">
    <xsl:copy>
      <xsl:apply-templates select="@*|node()"/>
    </xsl:copy>
  </xsl:template>

  <xsl:template match="weight">
    <Weight>
      <xsl:copy-of select="substring-before(.,'kg')"/>
    </Weight>

    <unitWeights>
      <xsl:copy-of select="substring(., string-length(.) - 1)"/>
    </unitWeights>
  </xsl:template>

  <xsl:template match="unitWeights"/>

</xsl:stylesheet>
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