Excel VBA格式化十六进制

2023年4月10日 376次阅读

我想将3位长的十六进制转换为6位数.例如12F shd是00012F.我尝试了这段代码,但它没有用.

endadd = Format(endadd, "000000")

最佳答案 正如Scott Craner指出的那样,一个简单的Right(“000000”和endadd,6)可以很好地工作,但Right $(“000000”& endadd,6)稍快一些.

此外,从性能角度来看,它实际上取决于endadd值的原始源是String还是Numeric.

'CONCAT String Approach
'If the hex source is a string, then this is the most efficient approach
formattedHex = Right$("000000" & "12F", 2)

'CONCAT Numeric Approach
'But if the hex source is a numeric, then this hex conversion AND concatenation is required, but it is SLOW
formattedHex = Right$("000000" & Hex$(&H12F), 2)

'ADDITION/OR Numeric Approach
'When the hex source is numeric it is more efficient to use a bit trick to add AND convert
formattedHex = Right$(Hex$(&H1000000 + &H12F), 2)
formattedHex = Right$(Hex$(&H1000000 Or &H12F), 2)

10米操作循环的结果：

Approach                  | Using Right | Using Right$|
==========================+=============================
CONCAT String Approach    | 1.59s       | 1.40s
CONCAT Numeric Approach   | 2.63s       | 2.33s
ADDITION Numeric Approach | 1.74s       | 1.60s
======================================================
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