玩2.5,休眠：表没有映射

2023年6月17日 177次阅读

我在下面得到了一个例外

(例外是：org.hibernate.hql.internal.ast.QuerySyntaxException：未映射用户)

调用此代码时发生.

TypedQuery<User> query = jpaApi.em().createQuery("select u from User u where u.email = :email and u.secretHash = :secretHash", User.class)
            .setParameter("email", parameter.getEmail())
            .setParameter("secretHash", hashAlgorithm.hash(parameter.getPassword()));

但是如果这个项目是通过“actirvator start”运行(开发env),则不会发生此异常.

它意味着……仅在生产环境中我得到了这个例外.

我该怎么办呢.

请帮我.

感谢您的帮助,我的项目信息如下

>系统环境：

1)比赛：2.5.4

2)休眠：5.2.1.final

>例外消息：

引起：org.hibernate.hql.internal.ast.QuerySyntaxException：用户未映射[从用户u中选择u,其中u.email =：email和u.secretHash =：secretHash]
    在org.hibernate.hql.internal.ast.QuerySyntaxException.generateQueryException(QuerySyntaxException.java:79)
    在org.hibernate.QueryException.wrapWithQueryString(QueryException.java:103)
    在org.hibernate.hql.internal.ast.QueryTranslatorImpl.doCompile(QueryTranslatorImpl.java:218)
    在org.hibernate.hql.internal.ast.QueryTranslatorImpl.compile(QueryTranslatorImpl.java:142)
    在org.hibernate.engine.query.spi.HQLQueryPlan.(HQLQueryPlan.java:115)
    在org.hibernate.engine.query.spi.HQLQueryPlan.(HQLQueryPlan.java:77)
    在org.hibernate.engine.query.spi.QueryPlanCache.getHQLQueryPlan(QueryPlanCache.java:152)
    在org.hibernate.internal.AbstractSharedSessionContract.getQueryPlan(AbstractSharedSessionContract.java:521)
    在org.hibernate.internal.AbstractSharedSessionContract.createQuery(AbstractSharedSessionContract.java:623)
    ……还有52个
引起：org.hibernate.hql.internal.ast.QuerySyntaxException：未映射用户
    在org.hibernate.hql.internal.ast.util.SessionFactoryHelper.requireClassPersister(SessionFactoryHelper.java:171)
    at org.hibernate.hql.internal.ast.tree.FromElementFactory.addFromElement(FromElementFactory.java:91)
    在org.hibernate.hql.internal.ast.tree.FromClause.addFromElement(FromClause.java:79)
    在org.hibernate.hql.internal.ast.HqlSqlWalker.createFromElement(HqlSqlWalker.java:321)
    在org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.fromElement(HqlSqlBaseWalker.java:3690)
    在org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.fromElementList(HqlSqlBaseWalker.java:3579)
    在org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.fromClause(HqlSqlBaseWalker.java:718)
    在org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.query(HqlSqlBaseWalker.java:574)
    在org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.selectStatement(HqlSqlBaseWalker.java:311)
    在org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.statement(HqlSqlBaseWalker.java:259)
    在org.hibernate.hql.internal.ast.QueryTranslatorImpl.analyze(QueryTranslatorImpl.java:262)
    在org.hibernate.hql.internal.ast.QueryTranslatorImpl.doCompile(QueryTranslatorImpl.java:190)
    ……还有58个
> persistence.xml

<persistence xmlns="http://java.sun.com/xml/ns/persistence"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd"
version="2.0">
<persistence-unit name="Hoth-PersistenceUnit" transaction-type="RESOURCE_LOCAL">
    <provider>org.hibernate.jpa.HibernatePersistenceProvider</provider>
    <non-jta-data-source>DefaultDS</non-jta-data-source>
    <properties>
        <property name="hibernate.dialect" value="org.hibernate.dialect.PostgreSQL94Dialect" />

        <property name="hibernate.show_sql" value="true" />
        <property name="hibernate.format_sql" value="true" />
        <property name="hibernate.use_sql_comments" value="true" />

        <property name="hibernate.max_fetch_depth" value="5" />

        <property name="hibernate.hbm2ddl.auto" value="update" />

        <property name="hibernate.jdbc.batch_size" value="50" />
        <property name="hibernate.jdbc.batch_versioned_data" value="true" />
        <property name="hibernate.order_inserts" value="true" />
    </properties>
</persistence-unit>

>实体类代码

@Entity
@Table (name = "users")
@Getter @Setter @ToString @EqualsAndHashCode (of = "email")
public class User {
@Id
private String email;

@Column(name = "secret_hash")
private String secretHash;

@Column(name = "accessed_at")
private LocalDateTime accessedAt;

private String gender;

@Column(name = "birth_year")
private Integer birthYear;

@Column(name = "picture_name")
private String pictureName;

@Column(name = "picture_url")
private String pictureUrl;

private String nickname;
}

最佳答案 persistence.xml中缺少用户映射.我无法从用户定义的包中看到片段,但我们假设它在包persistence.models中. persistence.xml应该是这样的：

<persistence-unit name="Hoth-PersistenceUnit" transaction-type="RESOURCE_LOCAL">
<provider>org.hibernate.jpa.HibernatePersistenceProvider</provider>
<non-jta-data-source>DefaultDS</non-jta-data-source>
<class>persistence.models.User</class>
<properties>
    ...
</properties>
点赞