我有一个Activity和两个片段用于包含viewpager的tablayout.
现在我可以通过实现谷歌的指南回调界面从片段到活动进行通信.但是,我怎样才能将其他方式从活动传达到片段?如果活动(外部事件)中发生了某些事情,我想更新片段.我设法得到了Frag1片段
MyFragmentPagerAdapter a = (MyFragmentPagerAdapter) viewPager.getAdapter();
Frag1 frag = (Frag1) a.getItem(0);
但是当我在frag上调用公共方法时,我得到一个IllegalStateException:片段没有附加到Activity可能是因为getItem(0)返回了一个新的Frag1实例而且还没有附加…是否有人可以为此提供一个干净的解决方案整个Viewpager – >片段交流的活动?
一些代码给你:
在活动中:
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
ViewPager viewPager = (ViewPager) findViewById(R.id.viewpager);
if (viewPager != null) {
viewPager.setAdapter(new MyFragmentPagerAdapter(getSupportFragmentManager()));
}
TabLayout tabLayout = (TabLayout) findViewById(R.id.sliding_tabs);
if (tabLayout != null) {
tabLayout.setupWithViewPager(viewPager);
}
}
活动布局:
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:tools="http://schemas.android.com/tools"
android:layout_width="match_parent"
android:layout_height="match_parent"
xmlns:app="http://schemas.android.com/apk/res-auto"
android:orientation="vertical"
tools:context="com.MainActivity">
<android.support.design.widget.TabLayout
android:id="@+id/sliding_tabs"
android:layout_width="match_parent"
android:layout_height="wrap_content"/>
<android.support.v4.view.ViewPager
android:id="@+id/viewpager"
android:layout_width="match_parent"
android:layout_height="0px"
android:layout_weight="1"/>
</LinearLayout>
MyFragmentPagerAdapter:
public class MyFragmentPagerAdapter extends FragmentPagerAdapter {
final int PAGE_COUNT = 2;
private String tabTitles[] = new String[] { "tab1", "tab2" };
public MyFragmentPagerAdapter(FragmentManager fm) {
super(fm);
}
@Override
public Fragment getItem(int position) {
switch (position) {
case 0:
return Frag1.newInstance(position + 1);
case 1:
return Frag2.newInstance(position + 1);
default:
return null;
}
}
@Override
public int getCount() {
return PAGE_COUNT;
}
@Override
public CharSequence getPageTitle(int position) {
return tabTitles[position];
}
}
Frag1:
public class Frag1 extends Fragment {
public static final String ARG_PAGE = "ARG_PAGE";
private int mPage;
private onFrag1InteractionListener mListener;
public Frag1() {
// Required empty public constructor
}
/**
* Use this factory method to create a new instance of
* this fragment using the provided parameters.
*
* @return A new instance of fragment Frag1.
*/
public static Frag1 newInstance(int page) {
Frag1 fragment = new Frag1();
Bundle args = new Bundle();
args.putInt(ARG_PAGE, page);
fragment.setArguments(args);
return fragment;
}
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
if (getArguments() != null) {
mPage = getArguments().getInt(ARG_PAGE);
}
}
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
Bundle savedInstanceState) {
View view = inflater.inflate(R.layout.fragment_1, container, false);
return view;
}
@Override
public void onAttach(Context context) {
super.onAttach(context);
if (context instanceof onFrag1InteractionListener) {
mListener = (onFrag1InteractionListener) context;
} else {
throw new RuntimeException(context.toString()
+ " must implement onFrag1InteractionListener");
}
}
@Override
public void onDetach() {
super.onDetach();
mListener = null;
}
public interface onFrag1InteractionListener {
// TODO: Update argument type and name
void onFrag1Interaction(Action action);
}
最佳答案 您需要设置一些事件侦听器逻辑,其中片段注册其所需事件的活动.片段应在创建时注册,并在销毁时注销.
然后,当事件发生时,活动将通过已注册的侦听器列表并通知它们事件.
我在this answer中给出了一个详细的例子.
您可以使用事件总线库来简化活动和片段之间的某些连接.