c# – sql查询计算每小时的数据输入

2023年11月21日 140次阅读

我想显示特定行的每小时(1小时时间间隔)内当前数据输入的计数,最后显示所有小时的累计.

表详情：

CREATE TABLE [dbo].[ProductTable] (
    [Id]         INT          IDENTITY (1, 1) NOT NULL,
    [ProductID]  INT          NOT NULL,
    [EmployeeID] INT          NOT NULL,
    [Operation]  VARCHAR (50) NOT NULL,
    [Section]    NCHAR (10)   NOT NULL,
    [Line]       INT          NOT NULL,
    [Date]       DATETIME     DEFAULT (getdate()) NULL,
    PRIMARY KEY CLUSTERED ([Id] ASC),
);

我正在使用Microsoft Visual Studio SQL服务器
我写了这么多,但不知道每小时都要概括一下

SELECT COUNT(Id) AS Expr1
FROM ProductTable
WHERE (Line = 2)
AND (CONVERT(VARCHAR(10), Date, 105) = CONVERT(VARCHAR(10), GETDATE(), 105))
AND (DATEPART(hour, GETDATE()) BETWEEN 9 AND 10)`

ProductTable数据
《c# – sql查询计算每小时的数据输入》

使用“案例”时出错
《c# – sql查询计算每小时的数据输入》

最佳答案 听起来你想按小时分组

SELECT      DATEPART(hour, date) as TimeOfDay,  COUNT(Id) AS Entries
FROM            ProductTable
WHERE        (Line = 2) AND cast ([date] as date) =cast (getdate() as date) 
GROUP BY DATEPART(hour, date)

要获得一天中所有小时的累计,请使用分组集

      SELECT       ISNULL(cast(DATEPART(hour,[date]) as varchar(5)),'Total') as TimeOfDay, COUNT(Id) AS Entries
        FROM            ProductTable
        WHERE        (Line = 2) AND cast ([date] as date) =cast (getdate() as date)  
        GROUP BY GROUPING SETS (DATEPART(hour, [date]) , ())
ORDER BY   ISNULL(cast(DATEPART(hour, [date]) as varchar(5)),'Total')
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