要求是对二维数组的行进行排序.我觉得我的代码非常接近完成,但我无法弄清楚为什么它没有显示已排序的数组.我忘了提到我们不允许使用预制的排序方法.问题很可能出在sortRows方法中.无论如何,这是我的代码:
public class RowSorting
{
public static void main(String[] args)
{
double[][] numbers = new double[3][3];
double[][] number = new double[3][3];
int run = 0;
String answer = "";
while (run == 0)
{
Scanner input = new Scanner(System.in);
System.out.print("Enter a 3-by-3 matrix row by row: ");
for(int row = 0; row < numbers.length; row++)
{
for(int column = 0; column < numbers[row].length; column++)
{
numbers[row][column] = input.nextDouble();
}
}
for(int row = 0; row < numbers.length; row++)
{
for(int column = 0; column < numbers[row].length; column++)
{
System.out.print(numbers[row][column] + " ");
}
System.out.print("\n");
}
System.out.println("The sorted array is: \n");
number = sortRows(numbers);
for(int row = 0; row < number.length; row++)
{
for(int column = 0; column < number[row].length; column++)
{
System.out.print(number[row][column] + " ");
}
System.out.print("\n");
}
System.out.print("\nWould you like to continue the program (y for yes or anything else exits): ");
answer = input.next();
if(answer.equals("y"))
{
continue;
}
else
break;
}
}
public static double[][] sortRows(double[][] m)
{
for(int j = 0; j < m[j].length - 1; j++)
{
for(int i = 0; i < m.length; i++)
{
double currentMin = m[j][i];
int currentMinIndex = i;
for(int k = i + 1; k < m[j].length; k++)
{
if(currentMin > m[j][i])
{
currentMin = m[j][i];
currentMinIndex = k;
}
}
if(currentMinIndex != i)
{
m[currentMinIndex][j] = m[j][i];
m[j][i] = currentMin;
}
}
}
return m;
}
}
最佳答案 它看起来像这个块:
if(currentMin > m[j][i])
{
currentMin = m[j][i];
currentMinIndex = k;
}
永远不会发生.因为你刚才将currentMin分配给m [j] [i]前面的两行.如果检查,我相信你想用k.就像是
if (currentMin > m[j][k]){
currentMin = m[j][k];
currentMinIndex = k;
}