我正在尝试让Pin进入页面,我创建了4个EditTexts,并在我的活动中创建了一个函数.我的问题是,当我单击退格按钮时,我想将当前EditText聚焦到Before(Back)EditText,但是Key listener不起作用.

逻辑很简单,当用户输入编辑文本的数字时,它会失去焦点,然后编辑文本会变得焦点,然后它会变成这样.但问题是当我点击后退空间我想在edittext之前返回再次输入数字.我试图在beforeTextChange中插入keyListener,但它没有工作.

 private void SetTextChange(final EditText etCurrent, final EditText etForward,final EditText etBack, final boolean isLast, final int currentPosition)
{

    etCurrent.addTextChangedListener(new TextWatcher() {
        @Override
        public void beforeTextChanged(CharSequence s, int start, int count, int after) {
        }

        @Override
        public void onTextChanged(CharSequence s, int start, int before, int count) {

            if (etCurrent.getText().length() == 1 && !isLast ) {
                etCurrent.setTypeface(null, Typeface.NORMAL);
                etCurrent.clearFocus();
                etForward.requestFocus();
                etForward.setCursorVisible(true);

                etCurrent.getBackground().setColorFilter(getResources().getColor(R.color.lavender_indigo), PorterDuff.Mode.SRC_ATOP);
            } else if (etCurrent.length() == 0) {
                etCurrent.getBackground().setColorFilter(getResources().getColor(R.color.french_gray), PorterDuff.Mode.SRC_ATOP);
                etCurrent.setTypeface(null, Typeface.SANS_SERIF.getStyle());

                etCurrent.setTypeface(null, Typeface.NORMAL);
                etCurrent.clearFocus();
                etBack.requestFocus();
                etBack.setCursorVisible(true);

            }


            if (etCurrent.length() != 0) {
                Integer currentKey = Integer.parseInt(etCurrent.getText().toString());
                keyList.set(currentPosition, currentKey);
            } else
                keyList.set(currentPosition, -1);

            if (keyList.size() > 3)
                showToast(keyList.get(0) + " " + keyList.get(1) + " " + keyList.get(2) + " " + keyList.get(3));

        }

        @Override
        public void afterTextChanged(Editable s) {

        }
    });

    /*curText.setOnFocusChangeListener(new View.OnFocusChangeListener() {
        public void onFocusChange(View arg0, boolean arg1) {
            curText = etCurrent;
            backText = etBack;
            curText.setText("");
        }

        });*/
    }

这也是我的EditText示例xml之一.(其他都是一样的)

  <EditText
        android:layout_column="1"
        android:layout_columnWeight="1"
        android:id="@+id/etActivationDigit1"
        android:layout_width="70dp"
        android:layout_height="wrap_content"
        android:textSize="80dp"
        android:textAlignment="center"
        android:gravity="center_horizontal"
        android:hint="*"
        android:textColorHint="@color/french_gray"
        android:backgroundTint="@color/french_gray"
        android:fontFamily="sans-serif"
        android:textColor="@color/perfume"
        android:maxLength="1"
        android:inputType="number"
         />

当用户输入错误的号码时,我只想擦除并重新聚焦.注意：当你填写所有字段时,你会看到你可以删除并返回,但我想回到密码的中间位置.谢谢.

  etCurrent.setOnKeyListener(new View.OnKeyListener() {
        @Override
        public boolean onKey(View v, int keyCode, KeyEvent event) {

            if(etCurrent.getText().toString() == "" && keyCode == event.KEYCODE_DEL)
            {
                etCurrent.setText("");
                etCurrent.clearFocus();
                etBack.requestFocus();
                etBack.setText("");
            }
            return false;
        }
    });

当我触摸退格键时,我的Backspace侦听器不会触发,但会触发所有其他字符.

最佳答案 这适用于我的4位密码活动.

private void setupInputListeners() {
    verificationCode1EditText.addTextChangedListener(new TextWatcher() {
        @Override
        public void beforeTextChanged(CharSequence s, int start, int count, int after) {
        }

        @Override
        public void onTextChanged(CharSequence s, int start, int before, int count) {
            if (s.length() == 1) {
                verificationCode2EditText.requestFocus(View.FOCUS_DOWN);
            }
        }

        @Override
        public void afterTextChanged(Editable s) {
        }
    });

    verificationCode2EditText.addTextChangedListener(new TextWatcher() {
        @Override
        public void beforeTextChanged(CharSequence s, int start, int count, int after) {
        }

        @Override
        public void onTextChanged(CharSequence s, int start, int before, int count) {
            if(count == 0) {
                verificationCode1EditText.requestFocus(View.FOCUS_DOWN);
            } else {
                if (s.length() == 1) {
                    verificationCode3EditText.requestFocus(View.FOCUS_DOWN);
                }
            }
        }

        @Override
        public void afterTextChanged(Editable s) {
        }
    });

    verificationCode3EditText.addTextChangedListener(new TextWatcher() {
        @Override
        public void beforeTextChanged(CharSequence s, int start, int count, int after) {
        }

        @Override
        public void onTextChanged(CharSequence s, int start, int before, int count) {
            if(count == 0) {
                verificationCode2EditText.requestFocus(View.FOCUS_DOWN);
            } else {
                if (s.length() == 1) {
                    verificationCode4EditText.requestFocus(View.FOCUS_DOWN);
                }
            }
        }

        @Override
        public void afterTextChanged(Editable s) {
        }
    });

    verificationCode4EditText.addTextChangedListener(new TextWatcher() {
        @Override
        public void beforeTextChanged(CharSequence s, int start, int count, int after) {
        }

        @Override
        public void onTextChanged(CharSequence s, int start, int before, int count) {
            if(count == 0) {
                verificationCode3EditText.requestFocus(View.FOCUS_DOWN);
            }
        }

        @Override
        public void afterTextChanged(Editable s) {
        }
    });
}