json.dumps() 是将一个Python数据结构转换为一个JSON编码的字符串 json.loads() 是将一个JSON编码的字符串转换为一个Python数据结构     如下： >>> import json >>> a={‘name’:’xiaoming’} >>> json.dumps(a) ‘{“name”: “xiaoming”}’ >>> b='{“name”: “xiaoming”}’ >>> json.loads(b) {u’name’: u’xiaoming’}     注意：我们原先定义a的元素都是用单引号，而dumps转化后都变成了双引号，而在loads后变成python变量时，元素都变成了单引号，并且字符串前加多了个u。   那么当我定义如下的字符串类型时，元素内容用单引号，而整个字符串用双引号括起来： >>> c=”{‘name’:’xiaoming’}” >>> print json.loads(c) Traceback (most recent call last): File “<stdin>”, line 1, in <module> File “/usr/local/python27/lib/python2.7/json/__init__.py”, line 339, in loads return _default_decoder.decode(s) File “/usr/local/python27/lib/python2.7/json/decoder.py”, line 364, in decode obj, end = self.raw_decode(s, idx=_w(s, 0).end()) File “/usr/local/python27/lib/python2.7/json/decoder.py”, line 380, in raw_decode obj, end = self.scan_once(s, idx) ValueError: Expecting property name: line 1 column 2 (char 1)   程序报错了，所以
一般要求当要字符串通过loads转为python数据类型时，得外层用单引号，里面元素key和value用双引号   还有，即使满足上述条件，当有u前缀的unicode出现修饰时，也会报错： >>> c='{u”name”: u”xiaoming”}’ >>> json.loads(c) Traceback (most recent call last): File “<stdin>”, line 1, in <module> File “/usr/local/python27/lib/python2.7/json/__init__.py”, line 339, in loads return _default_decoder.decode(s) File “/usr/local/python27/lib/python2.7/json/decoder.py”, line 364, in decode obj, end = self.raw_decode(s, idx=_w(s, 0).end()) File “/usr/local/python27/lib/python2.7/json/decoder.py”, line 380, in raw_decode obj, end = self.scan_once(s, idx) ValueError: Expecting property name: line 1 column 2 (char 1)  
所以loads在处理中，还需要把里面的u前缀修饰符去掉          https://stackoverflow.com/questions/25707558/json-valueerror-expecting-property-name-line-1-column-2-char-1     ———————————————————————————————————————————————————————————————————–