如何在struts2中只返回数组而不是json对象

2023年7月26日 221次阅读 
<action name="commissioner_info" method="commissioner_info" class="foo.bar.AdminInfoAction">
    <result name="json" type="json">    
        <param name="includeProperties">
            commissioner_info\[\d+\]\.fname,
            commissioner_info\[\d+\]\.designation,        
            commissioner_info\[\d+\]\.pathlocation
        </param>
    </result>
</action>

以上代码给出结果：

{"commissioner_info":[{"designation":"IG1","fname":"BS  Bassi ","pathlocation":"http:\/\/103.231.125.106\/nesos\/imagerepresentatives\/151021104556Bhim.jpg"}]}

但我只想要数组而不是json对象

[{"designation":"IG1","fname":"BS  Bassi ","pathlocation":"http:\/\/103.231.125.106\/nesos\/imagerepresentatives\/151021104556Bhim.jpg"}]

最佳答案 您需要将要序列化的对象指定为
the root object：

<result name="json" type="json">    
    <param name="root">
        commissioner_info
    </param>
</result>

否则整个动作将被序列化. Read more here.

点赞