c – WebRTC点对点连接

2023年6月30日 337次阅读

我正在使用C实现WebRTC Peer to Peer连接以进行音频呼叫.

我有两个线程_worker_thread和_signaling_thread.现在,当我尝试通过调用webrtc :: CreatePeerConnectionFactory()方法创建_peerConnectionFactory时,我的应用程序崩溃了.我怎样才能使它工作？

_signaling_thread.reset(new rtc::Thread());
if(!_signaling_thread->Start())
{
    printf("_signaling_thread is Failed");
    return;
}
_worker_thread.reset(new rtc::Thread());
if (!_worker_thread->Start()) {
    printf( "_worker_thread is Failed");
    return;
}

_peerConnectionFactory = webrtc::CreatePeerConnectionFactory(_worker_thread.get(),_signaling_thread.get(),NULL,NULL,NULL);

这是我得到的回溯

* thread #15: tid = 0x17e516, 0x00000001008d5674 MyAPP`rtc::MessageQueue::Get(rtc::Message*, int, bool) + 816, stop reason =  EXC_BAD_ACCESS (code=1, address=0x100000038)                                              
* frame #0: 0x00000001008d5674 MyAPP`rtc::MessageQueue::Get(rtc::Message*, int, bool) + 816
frame #1: 0x00000001008e5fb0 MyAPP`rtc::Thread::ProcessMessages(int) + 100
frame #2: 0x00000001008e5e44 MyAPP`rtc::Thread::PreRun(void*) + 88
frame #3: 0x0000000199337b3c libsystem_pthread.dylib`_pthread_body + 156
frame #4: 0x0000000199337aa0 libsystem_pthread.dylib`_pthread_start + 1

最佳答案 在查看WebRTC源代码中的PeerConnection示例之后,我总是在创建这样的线程之前初始化SSL模块：

bool Core::Init() {
  rtc::InitializeSSL();
  rtc::InitRandom(rtc::Time());
  rtc::ThreadManager::Instance()->WrapCurrentThread();

  _signalingThread = new rtc::Thread();
  _workerThread = new rtc::Thread();

  _signalingThread->SetName("signaling_thread", NULL);
  _workerThread->SetName("worker_thread", NULL);

  if (!_signalingThread->Start() || !_workerThread->Start()) {
    return false;
  }

  _peerConnectionFactory =
      webrtc::CreatePeerConnectionFactory(_signalingThread,
                                          _workerThread,
                                          NULL, NULL, NULL).release();

  return true;
}
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