如何更好地复制SQL Server中的一组数据

2024年1月24日 124次阅读

我有几个相关的表,我希望能够在更新引用时复制某些行.

我想复制Table1中的一行,以及Table2和Table3中所有相关的行,我试图找出一种有效的方法来完成迭代行.

例如,我有一张篮子桌子：

+----------+---------------+
| BasketId |  BasketName   |
+----------+---------------+
|        1 | Home Basket   |
|        2 | Office Basket |
+----------+---------------+

每个篮子都有水果：

+---------+----------+-----------+
| FruitId | BasketId | FruitName |
+---------+----------+-----------+
|       1 |        1 | Apple     |
|       2 |        1 | Orange    |
|       3 |        2 | Mango     |
|       4 |        2 | Pear      |
+---------+----------+-----------+

每种水果都有一些特性：

+------------+---------+--------------+
| PropertyId | FruitId | PropertyText |
+------------+---------+--------------+
|          1 |       2 | Is juicy     |
|          2 |       2 | Hard to peel |
|          3 |       1 | Is red       |
+------------+---------+--------------+

对于此示例,我的属性特定于单个水果行,这些“apple”属性不是所有篮子中所有苹果的属性,仅适用于该特定篮子中的特定苹果.

我想要做的是复制一个篮子.所以给了篮子1,我想创建一个新的篮子,复制它包含的果实行,并复制指向那些果实的属性.最后我希望有这样的数据：

+----------+---------------+
| BasketId |  BasketName   |
+----------+---------------+
|        1 | Home Basket   |
|        2 | Office Basket |
|        3 | Friends Basket|
+----------+---------------+

+---------+----------+-----------+
| FruitId | BasketId | FruitName |
+---------+----------+-----------+
|       1 |        1 | Apple     |
|       2 |        1 | Orange    |
|       3 |        2 | Mango     |
|       4 |        2 | Pear      |
|       5 |        3 | Apple     |
|       6 |        3 | Orange    |
+---------+----------+-----------+

+------------+---------+--------------+
| PropertyId | FruitId | PropertyText |
+------------+---------+--------------+
|          1 |       2 | Is juicy     |
|          2 |       2 | Hard to peel |
|          3 |       1 | Is red       |
|          4 |       6 | Is juicy     |
|          5 |       6 | Hard to peel |
|          6 |       5 | Is red       |
+------------+---------+--------------+

复制篮子和它的果实非常简单,但重复水果的属性似乎导致迭代行,我希望在TSQL中有更好的解决方案.

有任何想法吗？

最佳答案 为什么不加入FruitName来获得新旧FruitId的表格？考虑信息将同时添加….它可能不是最好的选择,但你不会使用任何周期.

INSERT INTO BASKET(BASKETNAME)
VALUES ('COPY BASKET')

DECLARE @iBasketId int
SET @iBasketId = @@SCOPE_IDENTITY;


insert into Fruit (BasketId, FruitName)
select @iBasketId, FruitName
from Fruit 
where BasketId = @originalBasket

declare @tabFruit table (originalFruitId int, newFruitId int)

insert into @tabFruit (originalFruitId, newFruitId)
select o.FruitId, n.FruitId
from (SELECT FruitId, FruitName from Fruit where BasketId = @originalBasket) as o
join (SELECT FruitId, FruitName from Fruit where BasketId = @newBasket) as n
    on o.FruitName = n.FruitName


insert into Property (FruitId, PropertyText)
select NewFruitId, PropertyText
from Fruit f join @tabFruit t on t.originalFruitId = f.FruitId
点赞