我想问你如何测试接受另一个类的构造函数实例的类.例如,我想测试方法’hasChildRoutes()’：

    class Route implements ng.route.IRoute {
    public url: string;
    public config: RouteConfig;

    constructor(url: string, config: RouteConfig) {
                this.url = url;
                this.config = config;
            }

    public hasChildRoutes(): boolean {
                return this.config.childRoutes.length > 0;
            }
}

我为此写了不好的单元测试(即时创建另一个类的新实例,这在我看来是不好的)：

 beforeEach(() => {
        routeSetting = new RouteSetting(1, '');
        routeConfig = new RouteConfig('', '', routeSetting, [], '');
    });


    describe('Methods test', () => {
        var childRoute: Route;

        beforeEach(() => {
            route = new Route('', routeConfig);
        });

        it('sould return false when Route has no child routes', () => {
            expect(route.hasChildRoutes()).toBeFalsy();
        });

        it('sould return true when Route has child routes', () => {
            routeConfig = new RouteConfig('', '', routeSetting, [route], '');
            route = new Route('', routeConfig);

            expect(route.hasChildRoutes()).toBeTruthy();
        });
    });

最佳答案 在arrange / act / assert中提供依赖项实例作为安排的一部分是完全有效的.

话虽如此,如果你想单独测试一个(这取决于b)你可以提供一个模拟b,例如使用sinonjs：http://sinonjs.org/