java – JPA / Hibernate尝试在具有复合Id(和加倍属性)的实体中存储太多参数

2023年4月1日 177次阅读

我有复合ID的实体

@Entity
@IdClass(value = BorrowId.class)
@Table(name = "BORROW")
public class Borrow {

    @Id
    @Column(name = "BOOK_ID", insertable = false, updatable = false)
    private long bookId;

    @Id
    @Column(name = "BORROWER_ID", insertable = false, updatable = false)
    private long borrowerId;

    @Id
    @ManyToOne(fetch = FetchType.LAZY, cascade = {CascadeType.PERSIST, CascadeType.MERGE, CascadeType.REFRESH})
    @JoinColumn(name = "BOOK_ID")
    private Book book;

    @Id
    @ManyToOne(fetch = FetchType.EAGER, cascade = {CascadeType.PERSIST, CascadeType.MERGE, CascadeType.REFRESH})
    @JoinColumn(name = "BORROWER_ID")
    private Borrower borrower;

    @Id
    @Column(name = "BORROW_DATE")
    private Date borrowDate;

    @Column(name = "RETURN_DATE")
    private Date returnDate;

BorrowId有属性(所有东西都有getter / setter)

    private long bookId;
    private long borrowerId;

    private Date borrowDate;

和equals,hashCode方法

当我试图坚持Borrow实体(书籍和借阅者属性设置为相应的实体,然后调用entityManager.persist(借用);)
我有我的日志：

Hibernate: insert into BORROW (BORROWER_ID, BOOK_ID, RETURN_DATE,
BORROW_DATE) values (?, ?, ?, ?) // this insert statement is correct
(that’s a look of my table) Invalid value “5” for parameter
“parameterIndex” [90008-174]

所以看起来有人做错了什么:)
怎么解决这个？我的实体声明有问题吗？ (我想用CompositeId来学习一些关于使用它的东西)

最佳答案 感谢@JB nizet

@Id
@Column(name = "BOOK_ID", insertable = false, updatable = false)
private long bookId;

@Id
@Column(name = "BORROWER_ID", insertable = false, updatable = false)
private long borrowerId;

@MapsId("bookId")
@ManyToOne(fetch = FetchType.LAZY, cascade = {CascadeType.PERSIST,
                                              CascadeType.MERGE,
                                              CascadeType.REFRESH})
@JoinColumn(name = "BOOK_ID")
private Book book;

@MapsId("borrowerId")
@ManyToOne(fetch = FetchType.EAGER, cascade = {CascadeType.PERSIST, 
                                               CascadeType.MERGE,
                                               CascadeType.REFRESH})
@JoinColumn(name = "BORROWER_ID")
private Borrower borrower;

@Id
@Column(name = "BORROW_DATE")
private Date borrowDate;

解决这个问题,很奇怪,因为在任何示例/教程中都没有@IdClass使用@MapsId.
我不确定现在是否需要@JoinColumn

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