我有以下示例数据:
{
"name": "Bob",
"mi": "K",
"martialStatus": "M",
"age": 30,
"city": "Paris",
"job": "Engineer"
}
{
"name": "Chad",
"mi": "M",
"martialStatus": "W",
"age": 31,
"city": "Paris",
"job": "Doctor"
}
{
"name": "Mel",
"mi": "A",
"martialStatus": "D",
"age": 31,
"city": "London",
"job": "Doctor"
}
{
"name": "Frank",
"mi": "F",
"martialStatus": "S",
"age": 30,
"city": "London",
"job": "Engineer"
}
我正在尝试编写一个mongo查询,它将返回以下格式的结果:
“peopleCount”:4,
“jobsList”:{
“工作”:“医生”,
“ageList”:[
{
“年龄”:31岁,
“cityList”:[
{
“城市”:“伦敦”,
“人”:[
{
“名字”:“梅尔”,
“martialStatus”:“D”
}
]
},
{
“城市”:“巴黎”,
“人”:[
{
“名字”:“乍得”,
“martialStatus”:“W”
}
]
},
{
“城市”:“柏林”,
…
…
]
}
]
}
要尝试前两个级别(jobsList和ageList),我正在尝试下面的内容
db.colName.aggregate([
{
$group: {
_id: { job: "$job" },
jobsList: {
$push: {
age: "$age",
city: "$city",
name: "$name",
martialStatus: "$martialStatus"
}
}
}
},
{
$group: {
_id: { age: "$age" },
ageList: {
$push: {
city: "$city",
name: "$name",
martialStatus: "$martialStatus"
}
}
}
}
]);
虽然第一组/推动部件工作,但上述方法不起作用…有关如何获得输出格式/灌浆的任何提示?
最佳答案
db.colName.aggregate([
{
$group: {
_id: { job: "$job", age: "$age", city: "$city" },
people: { $push: { name: "$name", martialStatus: "$martialStatus" } }
}
},
{
$group: {
_id: { job: "$_id.job", age: "$_id.age" },
peopleCount: { $sum: { $size: "$people" } },
cityList: { $push: { city: "$_id.city", people: "$people" } },
}
},
{
$group: {
_id: { job: "$_id.job" },
peopleCount: { $sum: "$peopleCount" },
agesList: { $push: { age: "$_id.age", cityList: "$cityList" } }
}
},
{
$group: {
_id: null,
peopleCount: { $sum: "$peopleCount" },
jobsList: { $push: { job: "$_id.job", agesList: "$agesList" } }
}
},
{
$project: { _id: 0, peopleCount: 1, jobsList: 1 }
}
]);
在你提供的集合给我结果
{
"peopleCount" : 4,
"jobsList" :
[
{
"job" : "Engineer",
"agesList" :
[
{
"age" : 30,
"cityList" :
[
{
"city" : "London",
"people" :
[
{ "name" : "Frank", "martialStatus" : "S" }
]
},
{
"city" : "Paris",
"people" :
[
{ "name" : "Bob", "martialStatus" : "M" }
]
}
]
}
]
},
{
"job" : "Doctor",
"agesList" :
[
{
"age" : 31,
"cityList" :
[
{
"city" : "London",
"people" :
[
{ "name" : "Mel", "martialStatus" : "D" }
]
},
{
"city" : "Paris",
"people" :
[
{ "name" : "Chad", "martialStatus" : "W" }
]
}
]
}
]
}
]
}
这似乎是正确的.想了想,我不确定这是最好的解决方案.我是聚合框架的新手.