php – 许多额外的字段没有保存

2023年12月17日 110次阅读

我正在运行SilverStripe 3.4

我找不到任何关于以编程方式保存许多关系额外字段的文档.以下代码根本不起作用：

foreach ($notifications as $notification) {
    $status = $notification
        ->Members()
        ->filter([
            "ID" => Member::currentUserID()
        ])
        ->first();
    $data['Read'] = $status->Read; // whenever I call this code, $status->Read is ALWAYS 0
    $status->Read = 1;
    $status->write();
}

ORM类：

class Notification extends DataObject {
    private static $belongs_many_many = [
        "Members" => "Member"
    ];
}

class Member extends DataObject {

    private static $many_many = array(
        "Notifications" => "Notification"
    );

    private static $many_many_extraFields = array(
        "Notifications" => array(
            "Read" => "Boolean"
        )
    );
}

我已经看到DataObject :: getChangedFields过滤掉了我的Read字段,因为它不是“数据库字段”

注意：我已覆盖Notification :: onBeforeWrite但是：

>我不认为这是被称为
>我在开头就有这个代码：

protected function onBeforeWrite() {
    parent::onBeforeWrite();
    $changedFields = $this->getChangedFields();
    if (isset($changedFields['Read']) && count($changedFields) == 1) {
        return;
    }
}

最佳答案 我找到了反直觉的答案：

foreach($notifications as $notification){
    $data = $notification->toMap();
    $list = $notification->Members()
        ->filter([
            "ID"=>Member::currentUserID()
        ]);
    $status = $list->first();
    $data['Read'] = $status->Read;

    $list->add(Member::currentUserID(),[
        "Read"=>1
    ]);
}

这没有任何意义(将已经列在列表中的内容添加到列表中),但它确实有效.我希望他们更新这个.

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