我有两张桌子.
上传者 – id,名称,图标,视图
视频 – ID,上传者,视频,观看次数
上传者列用作视频上传者的参考.所以,我可以使用sum()函数来计算每个用户从他的所有视频中总共有多少视图.现在我想通过desc总视图来订购这些用户.
我该怎么做呢?继承了我到目前为止所拥有的代码……
//Retrieve data from the database
$fkbar = mysql_query("SELECT * FROM freaks");
while($fkrow = mysql_fetch_array($fkbar))
//Echo Theme Template on pages
{
$frkid = $fkrow['id'];
$viewq = mysql_query("SELECT SUM(views) AS vw FROM videos WHERE ref1='{$frkid}' OR ref2='{$frkid}' OR ref3='{$frkid}'");
while($viewcnt = mysql_fetch_array($viewq))
{
$viewcount = $viewcnt['vw'];
echo "<div class='diva' id='{$viewcount}'>";
echo "<div class='inner-diva'><a href='/mobile/freaks/?i={$fkrow['id']}'>";
echo "<img id='{$fkrow['id']}' class='dvBarIco' src='/assets/ico/{$fkrow['icon']}' height='80px'></a></div>";
echo "</div>";
}
}
最佳答案 只需使用聚合添加ORDER BY子句:
ORDER BY SUM(views) DESC
从您的评论中,您可以在第一个中使用子查询来进行排序:
SELECT *
FROM freaks f
ORDER BY (SELECT SUM(views) FROM videos WHERE ref1=f.id OR ref2=f.id OR ref3=f.id) DESC
您也可以使用连接执行此操作,但OR可能会使事情变得复杂:
SELECT f.*, COALESCE(v.views, 0) total_views
FROM freaks f
LEFT OUTER JOIN (
SELECT SUM(views) views, id
FROM (
SELECT views, ref1 AS id
FROM videos
UNION ALL
SELECT views, ref2 AS id
FROM videos
UNION ALL
SELECT views, ref3 AS id
FROM videos
) x
GROUP BY id
) v ON f.id = v.id
ORDER BY total_views DESC