我尝试了很多方法,但没有得到预期的结果.我怎样才能得到预期的结果.
你可以从这里下载dbtable structure: –
SELECT
IF(o.source_id = 1, 'online',0) TYPE,
MONTH(date_created) AS monthvalue
,SUM(total_price) AS totalSale
FROM orders o
WHERE o.source_id = 1 AND date_created BETWEEN(CURDATE() - INTERVAL 1 MONTH)
AND CURDATE()
GROUP BY monthvalue
UNION ALL
SELECT
IF(o.source_id = 2, 'visit',0) TYPE,
MONTH(date_created) AS monthvalue
,SUM(total_price) AS totalSale
FROM orders o
WHERE o.source_id =2 AND date_created BETWEEN(CURDATE() - INTERVAL 1 MONTH)
AND CURDATE()
GROUP BY monthvalue
UNION ALL
SELECT
IF(o.source_id = 3, 'phone',0) TYPE,
MONTH(date_created) AS monthvalue
,SUM(total_price) AS totalSale
FROM orders o
WHERE o.source_id = 3 AND date_created BETWEEN(CURDATE() - INTERVAL 1 MONTH)
AND CURDATE()
GROUP BY monthvalue
得到的结果: –
TYPE monthvalue totalSale
online 6 38300
visit 6 16800
phone 5 500
phone 6 7150
预期结果 :
Type May June
online 0 38300
Visit 0 16800
Phone 500 7150
最佳答案 根据您的数据库架构,如果您只是想要预期的结果,请尝试以下sql;)
select
case source_id when 1 then 'online' when 2 then 'visit' when 3 then 'phone' end as `Type`,
sum(if(month(date_created) = 5, total_price, 0)) as `May`,
sum(if(month(date_created) = 6, total_price, 0)) as `June`
from `orders`
where date_created between (curdate() - interval 1 month) and curdate()
group by source_id