我有两个实体技能及其类型SkillType.这种关系看起来如下:
/**
* @ORM\Entity
* @ORM\Table(name="skills")
*/
class Skill
{
/**
* @ORM\Id
* @ORM\Column(type="integer")
* @ORM\GeneratedValue(strategy="AUTO")
*/
protected $id;
/**
* @var SkillType
* @ORM\ManyToOne(targetEntity="SkillType", inversedBy="skills")
* @ORM\JoinColumn(name="type_id", referencedColumnName="id")
*/
protected $type;
//Getters and Setters
}
/**
* @ORM\Entity
* @ORM\Table(name="skill_types")
*/
class SkillType
{
/**
* @ORM\Id
* @ORM\Column(type="integer")
* @ORM\GeneratedValue(strategy="AUTO")
*/
protected $id;
/**
* @var Skill[]|ArrayCollection
* @ORM\OneToMany(targetEntity="AppBundle\Entity\Skill", mappedBy="type")
*/
protected $skills;
/**
* SkillType constructor.
*/
public function __construct()
{
$this->skills = new ArrayCollection();
}
//Getters and Setters
}
我还有一个形式创建这两个关系beetwen
class SkillType extends AbstractType
{
/**
* @inheritDoc
*/
public function buildForm(FormBuilderInterface $builder, array $options)
{
$builder
->add('type', EntityType::class, [
'multiple' => false,
'class' => 'AppBundle\Entity\SkillType',
'choice_label' => 'id',
'by_reference' => false
]);
}
/**
* @inheritDoc
*/
public function configureOptions(OptionsResolver $resolver)
{
$resolver->setDefaults([
'data_class' => 'AppBundle\Entity\Skill',
]);
}
}
我是如何尝试修复错误的?
>添加,cascade = {“persist”}到两侧的映射
>添加$entityManager->合并($entity);在createForm之前(SkillType :: class,$entity
我的请求内容如下所示:{“skill”:{“type”:1},“id”:“1”}.因此,您可以看到它应该在具有id = 1的Skill和具有id = 1的SkillType之间创建关系.
我提交表单时收到的错误是:
必须管理传递到选择字段的实体.也许坚持他们在实体经理?
堆栈跟踪:
Symfony\Component\Form\Exception\RuntimeException: Entities passed to the choice field must be managed. Maybe persist them in the entity manager?
at n/a
in /var/www/public_html/api-hb/vendor/symfony/symfony/src/Symfony/Bridge/Doctrine/Form/ChoiceList/IdReader.php line 119
at Symfony\Bridge\Doctrine\Form\ChoiceList\IdReader->getIdValue(object(SkillType))
in /var/www/public_html/api-hb/vendor/symfony/symfony/src/Symfony/Bridge/Doctrine/Form/ChoiceList/DoctrineChoiceLoader.php line 122
at Symfony\Bridge\Doctrine\Form\ChoiceList\DoctrineChoiceLoader->loadValuesForChoices(array(object(SkillType)), array(object(IdReader), 'getIdValue'))
in /var/www/public_html/api-hb/vendor/symfony/symfony/src/Symfony/Component/Form/ChoiceList/LazyChoiceList.php line 134
at Symfony\Component\Form\ChoiceList\LazyChoiceList->getValuesForChoices(array(object(SkillType)))
in /var/www/public_html/api-hb/vendor/symfony/symfony/src/Symfony/Component/Form/Extension/Core/DataTransformer/ChoiceToValueTransformer.php line 37
at Symfony\Component\Form\Extension\Core\DataTransformer\ChoiceToValueTransformer->transform(object(SkillType))
in /var/www/public_html/api-hb/vendor/symfony/symfony/src/Symfony/Component/Form/Form.php line 1092
at Symfony\Component\Form\Form->normToView(object(SkillType))
in /var/www/public_html/api-hb/vendor/symfony/symfony/src/Symfony/Component/Form/Form.php line 352
at Symfony\Component\Form\Form->setData(object(SkillType))
in /var/www/public_html/api-hb/vendor/symfony/symfony/src/Symfony/Component/Form/Extension/Core/DataMapper/PropertyPathMapper.php line 57
at Symfony\Component\Form\Extension\Core\DataMapper\PropertyPathMapper->mapDataToForms(object(Skill), object(RecursiveIteratorIterator))
in /var/www/public_html/api-hb/vendor/symfony/symfony/src/Symfony/Component/Form/Form.php line 385
at Symfony\Component\Form\Form->setData(object(Skill))
in /var/www/public_html/api-hb/vendor/symfony/symfony/src/Symfony/Component/Form/Form.php line 477
at Symfony\Component\Form\Form->initialize()
in /var/www/public_html/api-hb/vendor/symfony/symfony/src/Symfony/Component/Form/FormBuilder.php line 226
at Symfony\Component\Form\FormBuilder->getForm()
in /var/www/public_html/api-hb/vendor/symfony/symfony/src/Symfony/Component/Form/FormFactory.php line 39
最佳答案 我想这可能是db模式中的错误.首先检查你的数据库结构,如果我是正确的问题可能会发生在那里.我的概念是删除这种关系,运行doctrine schema update并再次创建这种关系.
我认为只在一个实体中出现此错误的原因没有在DB中正确反映,原因是之前的一些更改,即学说无法在架构更新中正确处理.