我试图从_.each中的$http中获取多个数据,并在$scope.tasksData中显示组合数据.
但问题是_.each稍后执行并首先返回null,
请指导如何解决此问题.
谢谢
var tasksList, processingStageId;
var apiURL = "http://localhost:9080/caseDetails/" + $stateParams.caseId + "?_=1461046349867";
var stagesList = $http.get(apiURL).then(function(resdata, status, headers, config) {
return resdata;
}).then(function(stagesData) {
stageId = stagesData.data.childStages;
var allTasksData = [];
var self = this;
_.each(stageId, function(item) {
var stagesApiURL = "http://localhost:9080/stageDetails/" + item.stage.stageId;
$http.get(stagesApiURL).then(function(taskData, status, headers, config) {
//_.extend(allTasksData, taskData.data);
allTasksData.push(taskData.data);
});
});
return allTasksData;
}).then(function(allTasksData) {
console.log("Hello");
_.each(allTasksData, function(data) {
$scope.tasksData.concat(data);
});
});
最佳答案 要在解决所有请求后获取数据,请使用$q.all([prom,prom,prom])
.then(function(stagesData){
var stageId = stagesData.data.childStages;
var tasks = [];
_.each(stageId, function(item){
var stagesApiURL = "http://localhost:9080/stageDetails/" + item.stage.stageId;
var req = $http.get(stagesApiURL).then(function(taskData, status, headers, config){
return taskData.data;
});
tasks.push(req);
});
//Merge all promise request. Resolve when all request resolved
return $q.all(tasks);
})
/**
* allTasksData - [taskData.data, taskData.data , ...]
*/
.then(function(allTasksData){
...
});