LuaSocket服务器：accept()超时(TCP)

2024年1月16日 383次阅读

问题

在LuaSocket Introduction之后,我设法让服务器运行.我还设法从客户端连接.但是,我注意到服务器脚本冻结,直到server：accept()获得连接.

研究

LuaSocket Reference规定：

Use the settimeout method or accept might block until another client shows up.

这甚至包含在示例代码中.但是,client：settimeout(10)在本地client = server：accept()之后调用,因此脚本在到达此点之前被阻塞.

我读到这可以通过多线程来解决,但这似乎是夸大其词.

问题

>如何使服务器脚本停止等待连接并继续？
>我如何防范客户端的类似问题：receive()(服务器端)和tcp：receive()(客户端)(或客户端：settimeout(10)负责)？

码

服务器(来自LuaSocket Introduction)

-- load namespace
local socket = require("socket")
-- create a TCP socket and bind it to the local host, at any port
local server = assert(socket.bind("*", 0))
-- find out which port the OS chose for us
local ip, port = server:getsockname()
-- print a message informing what's up
print("Please telnet to localhost on port " .. port)
print("After connecting, you have 10s to enter a line to be echoed")
-- loop forever waiting for clients
while 1 do
  -- wait for a connection from any client
  local client = server:accept()
  -- make sure we don't block waiting for this client's line
  client:settimeout(10)
  -- receive the line
  local line, err = client:receive()
  -- if there was no error, send it back to the client
  if not err then client:send(line .. "\n") end
  -- done with client, close the object
  client:close()
end

客户(见this answer)

local host, port = "127.0.0.1", 100
local socket = require("socket")
local tcp = assert(socket.tcp())

tcp:connect(host, port);
--note the newline below
tcp:send("hello world\n");

while true do
    local s, status, partial = tcp:receive()
    print(s or partial)
    if status == "closed" then break end
end
tcp:close()

最佳答案 您应该能够在调用server：accept()之前使用
server:timeout()：

server:settimeout(2)
local client, err = server:accept()
print(client, err)

如果2秒内没有请求,我会打印nil超时.

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