我正在研究一个口袋妖怪战斗模拟器,(基本上是pokemonshowdown gen1),试图自动化制作口袋妖怪阵列,但遇到了扫描仪问题.文件格式为：Name.Type1.Type2.hp.attack.defense.special.speed.list可学习的动作.所以：

Aerodactyl.Flying.Rock.80.105.65.60.130.Agility,Bide,Bite,Double-Edge,Double Team,Dragon Rage,Fire Blast,Fly,Hyper Beam,Mimic,Rage,Razor Wind,Reflect,Rest,Sky Attack,替补,超音速,迅速,击倒,有毒,翼攻击.

我有一个方法适用于我的typeArray和moveArray但由于某些原因使用基本相同的循环,扫描仪返回空标记而不是文件中的内容.

例外：

0   Exception in thread "main" java.lang.NumberFormatException: For input string: ""
at java.lang.NumberFormatException.forInputString(NumberFormatException.java:65)
at java.lang.Integer.parseInt(Integer.java:592)
at java.lang.Integer.parseInt(Integer.java:615)
at Controller.initPokemonArray(Controller.java:169)
at Controller.<init>(Controller.java:29)
at Driver.main(Driver.java:15)

这是整个方法,它在hp的parseInt调用中抛出错误.

    private Pokemon[] initPokemonArray() {
    Pokemon[] pokemonArray = new Pokemon[83];
    try {
        Scanner inputScan = new Scanner(new File("src/pokemon")).useDelimiter(".");
        String name = "";
        Type type1 = typeArray[0];
        String inputType1 = "";
        Type type2 = typeArray[0];
        String inputType2 = "";
        int hp = 0;
        int atk = 0;
        int def = 0;
        int spc = 0;
        int spe = 0;
        String[] lm = {};
        Move[] learnableMoves;
        int counter = 0;
        while (counter < 83) {
        System.out.print(counter);
            if (inputScan.hasNextLine()) {
                name = inputScan.next();
                System.out.println(name+" ");
                //System.out.print("name");
                inputType1 = inputScan.next();
                for (int i = 0;i < 16;i++)
                    if (inputType1.equals(typeArray[i].toString()))
                        type1 = typeArray[i];
                System.out.println(type1.toString()+" ");
                inputType2 = inputScan.next();
                for (int i = 0;i < 16;i++)
                    if (inputType2.equals(typeArray[i].toString()))
                        type2 = typeArray[i];
                System.out.println(type2.toString()+" ");
                hp = Integer.parseInt(inputScan.next());
                System.out.println(hp+" ");
                atk = Integer.parseInt(inputScan.next());
                System.out.println(atk+" ");
                def = Integer.parseInt(inputScan.next());
                System.out.println(def+" ");
                spc = Integer.parseInt(inputScan.next());
                System.out.println(spc+" ");
                spe = Integer.parseInt(inputScan.next());
                System.out.println(spe+" ");
                lm = inputScan.next().split(",");
                System.out.println();
            }
            //TODO move this to private helper method
            learnableMoves = new Move[lm.length];
            for (int i = 0;i < 160;i++) {
                for (int j = 0;j < lm.length;j++) {
                    if (lm[j] == moveArray[i].getName())
                        learnableMoves[j] = moveArray[i];
                }
            }
            pokemonArray[counter] = new Pokemon(name,type1,type2,hp,atk,def,spc,spe,learnableMoves);
            counter++;
        }
        inputScan.close();
    } catch (FileNotFoundException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
    return pokemonArray;
}

免责声明：这是我的java 2课程的一个项目,也是我在这里的第一篇文章,所以我不知道我应该做什么,所以只是让它在这里知道.

最佳答案 useDelimiter()方法将传递的String作为regex值.
https://docs.oracle.com/javase/8/docs/api/java/util/Scanner.html#useDelimiter-java.lang.String-.期间在正则表达式中具有特定含义.获取特定字符“.”用这个.

Scanner inputScan = new Scanner(new File("src/pokemon")).useDelimiter("\\.");