在我的实体上,我有一个用户的数组集合
/**
* @ORM\ManyToMany(targetEntity="\UserBundle\Entity\User", mappedBy="acr_groups")
*/
protected $users;
public function __construct() {
$this->users = new \Doctrine\Common\Collections\ArrayCollection();
}
在我的FormType中,我想过滤掉当前用户所属的组:
$builder
->add('acr_group', EntityType::class, array(
'label' => 'ATS',
'class' => 'HazardlogBundle:ACRGroup',
'query_builder' => function (EntityRepository $er) use ($user) { // 3. use the user variable in the querybilder
$qb = $er->createQueryBuilder('g');
$qb->where(':user IN (g.users)');
$qb->setParameters( array('user' => $user) );
$qb->orderBy('g.name', 'ASC');
return $qb;
},
'choice_label' => 'name'
))
我的问题显然是在这一行:
$qb->where(':user IN (g.users)');
如何使用我的用户集合作为IN()的参数?
最佳答案 试试下面的代码
$user = array(12,211,612,84,63,23); // Assuming User Ids whose groups you want to retrive
$builder
->add('acr_group', EntityType::class, array(
'label' => 'ATS',
'class' => 'HazardlogBundle:ACRGroup',
'query_builder' => function (EntityRepository $er) use ($user) {
$qb = $er->createQueryBuilder('g');
$qb->innerJoin('g.users', 'u'); // Inner Join with users
$qb->where('u.id IN (:user)');
$qb->setParameters( array('user' => $user) );
$qb->orderBy('g.name', 'ASC');
return $qb;
},
'choice_label' => 'name'
))
我已经在symfony 2.3中使用doctrine2进行了尝试.您可以使用select函数和createQueryBuilder()来获取特定列.