尝试返回char指针时输出奇怪

2019年7月20日 199次阅读

编辑：我删除了内存分配声明,并将strlen(bufferPointer)更改为strlen(inputLine).这似乎摆脱了我的输出中的奇怪符号.

我正在尝试编写一个方法来删除字符串中的第一个单词,并返回删除单词的char指针.因为删除了这个单词,所以应该减少字符串的大小.

我遇到了一个奇怪的输出,我不知道为什么.

我是C的新手,刚刚开始熟悉指针的想法,所以任何帮助都将不胜感激！

//global variables
char inputLine[] = "Hello there, my name is bob"; 
char *bufferPointer = inputLine;
char *nextWord();

main (){
    printf("%s\n", nextWord());
}

char *nextWord(){
    //calling a method that returns the number of words bufferPointer holds
    int numOfWords = nwords(bufferPointer);
    char *tmp2;

    //Allocate memory to newArray
    char *newArray = malloc(sizeof(char)*strlen(bufferPointer));

    //create backup array
    char backup[strlen(bufferPointer)];
    strncpy(backup, bufferPointer, strlen(bufferPointer));
    backup[strlen(bufferPointer)] = '\0';

    //assign newArray pointer to backup array
    newArray = backup;

    //allocate memory to token (returned variable)
    char *token = malloc(sizeof(char)*strlen(bufferPointer));
    token = strtok(newArray, " ");

    char *tmp = strchr(bufferPointer, ' ');
    //move pointer to next word
    if (tmp != NULL){
        tmp2 = tmp;
        bufferPointer = tmp +1;
    }
   return token;
}

旧输出是：

there,
my
?²p
??
?²p?
?²p?

新产出是：

there,
my
name
is
bob

最佳答案 strlen()仅为您提供字符数,不包括空字符.您还需要为空字符分配内存.

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