php – 使用Symfony Security的简单登录表单

2023年11月13日 181次阅读

我尝试使用本教程登录表单：
http://symfony.com/doc/current/cookbook/security/form_login_setup.html

所以,现在我的security.yml文件看起来像：

security:
    providers:
        in_memory:
            memory:
                users:
                    ryan:
                        password: ryanpass
                        roles: 'ROLE_USER'
                    admin:
                        password: kitten
                        roles: 'ROLE_ADMIN'

    encoders:
      Symfony\Component\Security\Core\User\User: plaintext

    firewalls:
        login_firewall:
            pattern:   ^/login$
            anonymous: ~
        secured_area:
            pattern:    ^/
            anonymous: ~
            form_login:
              login_path: login
              check_path: login
        dev:
            pattern: ^/(_(profiler|wdt)|css|images|js)/
            security: false

    access_control:
        - { path: ^/login, roles: IS_AUTHENTICATED_ANONYMOUSLY }
        - { path: ^/, roles: ROLE_USER }

安全控制器：

class SecurityController extends Controller
{
    /**
     * @Route("/login", name="login")
     */
    public function loginAction(Request $request)
    {
        $authenticationUtils = $this->get('security.authentication_utils');

        // get the login error if there is one
        $error = $authenticationUtils->getLastAuthenticationError();

        // last username entered by the user
        $lastUsername = $authenticationUtils->getLastUsername();

        return $this->render(
            'AppBundle:Security:login.html.twig',
            array(
                // last username entered by the user
                'last_username' => $lastUsername,
                'error'         => $error,
            )
        );
    }

}

所以基本上,它不能正常工作.发送登录表后没有任何反应,我不知道为什么.我认为安全性的配置是错误的.有人能帮助我吗？我不知道出了什么问题.

最佳答案 将check_path更改为其他内容,例如login_check,并将login_check和logout操作添加到控制器：

/**
 * @Route("/login_check", name="login_check")
 */
public function loginAction()
{
    // The security layer will intercept this request, else redirect to login page
    $this->addFlash('warning', $this->get('translator')->trans('login_expired'));
    return $this->redirect($this->generateUrl('login'));
}

/**
 * @Route("/logout", name="logout")
 */
public function logoutAction()
{
    // The security layer will intercept this request, else redirect to login page
    $this->addFlash('warning', $this->get('translator')->trans('login_expired'));
    return $this->redirect($this->generateUrl('login'));
}

还要确保login_form为login_check发帖：

<form id="loginForm" action="{{ path('login_check') }}" method="post">
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