我有一个
python脚本,它打开一个端口并在Raspberry上监听它.我把它添加到/etc/rc.local
一切正常.但我的问题是在执行进程时未创建的套接字.
s = socket.socket()
s.bind((host_ip,port)) #e.g. host_ip='192.168.1.32' , port=12345
s.listen(5)
while True:
c,addr = s.accept()
c.send('ACK')
c.close()
上述代码未执行,因为没有’eth0’连接可用.我该怎么办?我应该循环扫描套接字状态,直到连接可用吗?还有其他更复杂的解决方案吗?
最佳答案 像这样:
import urllib2,thread
from time import sleep
import netifaces
class _check:
def __init__(self):
self.uri="http://www.google.com"
self.period = 5
self.status = False
self.ifaces()
def check(self):
try:
answ = urllib2.urlopen(self.uri)
if answ:
self.status = True
#Now can run your awesome code !
print "okay go take a beer"
except Exception,e : print e
def timer(self,pass_arg) :
while True :
if self.status != True :
self.check()
sleep(self.period)
print "running"
elif self.status == True :
print "thread ending"
break
def ifaces(self):
for i in netifaces.interfaces() :
try:
print i,netifaces.ifaddresses(i)[2]
except:
print i, "iface not up !"
check = _check()
thread.start_new_thread(check.timer,(None,))
所以这个答案等于我的评论答案.