python的post请求实例

2023年1月15日 232次阅读 来源: xxt_ 
#coding=utf-8
import json
import urllib2
import base64
import sys

# start=sys.argv[1]
# end=sys.argv[2]
# DEFAULT_URL =""
DEFAULT_URL =""
auth = base64.b64encode("admin" + ':' + "admin")


for i in range(1):
    body = [{
            
            "Tag":"hhhuuuuuuu",
            "Type":"rr"
    }]
#     body = {"name":"hhnnnnnnnnnnnnnnnnnn","desc":"bbbbbbbbbbbbbbbbbb"}
    print(type(body))
    j_data = json.dumps(body)
    print(type(j_data))
    print(j_data)
    
    
    headers = {
                "Authorization": "Basic " + auth,
                "Accepty":"application/json, text/plain, */*",
                "Accept-Encoding": "gzip, deflate",
                "Accept-Language":"zh-CN,zh;q=0.9",
                "Connection":"keep-alive",
                "Content-Length":"363",
                "Content-Type":"application/json;charset=UTF-8",
                "User-Agent":"Mozilla/5.0 (Windows NT 6.1; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/65.0.3325.181 Safari/537.36",
                "X-Requested-By":"Data Collector"   
                } 
   
    post_request = urllib2.Request(DEFAULT_URL, data=j_data, headers=headers)
#     post_request.add_header( "Authorization", "Basic " + auth)
    #post_request.get_method = lambda: 'POST'
    mydict=post_request.__dict__
    print mydict
    try:
      post_response = urllib2.urlopen(post_request)
    except urllib2.HTTPError, e:
      print e.read()
 
    
    
#     get_request = urllib2.Request(DEFAULT_URL)
#     get_request.add_header( "Authorization", "Basic " + auth)
#     get_request.add_header("User-Agent","Mozilla/5.0 (Windows NT 6.1; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/65.0.3325.181 Safari/537.36")
#     get_request.get_method = lambda: 'GET'
#     get_response = urllib2.urlopen(get_request)
#     result =get_response.read()
#     print(result)

 

    原文作者：xxt_
    原文地址: https://blog.csdn.net/xxmonstor/article/details/81332223
    本文转自网络文章，转载此文章仅为分享知识，如有侵权，请联系博主进行删除。
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