最近正好有点时间,就整理了一下牛客网上的数据库SQL实战中的题,里面的每一道题我都亲自编写并运行了一下,有的题可能不止一个解,并且有些做了备注与分析。这里的题很具有代表性,对于软件开发人员有很大帮助,开发人员需要理解这些题,然后做到举一反三应用到实际的工作中去,当然最重要的还是贵在积累。
注:数据库sql实战中用的是sqlite3数据库,这里面的脚本都能在sqlite3中运行,有些还给出了在mysql、oracal等数据库上的运行脚本
1、查找最晚入职员工的所有信息
表结构说明
CREATE TABLE `employees` (
`emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));
脚本 1
select *
from employees
order by hire_date desc limit 1;
运行时间:17ms
占用内存:3320k
脚本 2
select *
from employees
where hire_date = (select max(hire_date) from employees);
运行时间:25ms
占用内存:3300k
2、查找入职员工时间排名倒数第三的员工所有信息
表结构说明
CREATE TABLE `employees` (
`emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));
脚本 1
select *
from employees
order by hire_date desc limit 2,1;
运行时间:31ms
占用内存:4332k
脚本 2
select *
from employees
where hire_date = (select hire_date from employees order by hire_date desc limit 2,1);
运行时间:18ms
占用内存:3284k
3、查找各个部门当前(to_date=’9999-01-01′)领导当前薪水详情以及其对应部门编号dept_no
表结构说明
CREATE TABLE `dept_manager` (
`dept_no` char(4) NOT NULL,
`emp_no` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));
CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`from_date`));
脚本 1
select s.*,d.dept_no
from salaries s, dept_manager d
where s.to_date='9999-01-01'
and d.to_date='9999-01-01'
and s.emp_no = d.emp_no;
运行时间:24ms
占用内存:3304k
4、查找所有已经分配部门的员工的last_name和first_name
表结构说明
CREATE TABLE `dept_emp` (
`emp_no` int(11) NOT NULL,
`dept_no` char(4) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));
CREATE TABLE `employees` (
`emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));
脚本 1
select e.last_name, e.first_name, d.dept_no
from dept_emp d
inner join employees e
on e.emp_no=d.emp_no;
运行时间:19ms
占用内存:3284k
5、查找所有员工的last_name和first_name以及对应部门编号dept_no,也包括展示没有分配具体部门的员工
表结构说明
CREATE TABLE `dept_emp` (
`emp_no` int(11) NOT NULL,
`dept_no` char(4) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));
CREATE TABLE `employees` (
`emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));
脚本 1
select e.last_name, e.first_name, d.dept_no
from employees e
left join dept_emp d
on e.emp_no=d.emp_no;
运行时间:19ms
占用内存:3284k
6、查找所有员工入职时候的薪水情况,给出emp_no以及salary, 并按照emp_no进行逆序
表结构说明
CREATE TABLE `employees` (
`emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));
CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`from_date`));
脚本 1
select s.emp_no, s.salary
from salaries s, employees e
where s.emp_no=e.emp_no
and s.from_date = e.hire_date
order by s.emp_no desc;
运行时间:29ms
占用内存:3284k
脚本 2
select s.emp_no, s.salary
from salaries s
inner join employees e
on s.emp_no=e.emp_no
and s.from_date = e.hire_date
order by s.emp_no desc;
运行时间:29ms
占用内存:3304k
脚本 3
select emp_no, salary
from salaries
group by emp_no
having min(from_date)
order by emp_no desc;
运行时间:22ms
占用内存:3436k
7、查找薪水涨幅超过15次的员工号emp_no以及其对应的涨幅次数t
表结构说明
CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`from_date`));
脚本 1
select emp_no, count(emp_no) as t
from salaries
group by emp_no having t > 15;
运行时间:32ms
占用内存:4180k
脚本 2
select emp_no, count(distinct salary) as t
from salaries group by emp_no having t > 15;
运行时间:26ms
占用内存:3416k
脚本 3
select e.emp_no, count(e.emp_no) as t
from (select emp_no, salary
from salaries group by emp_no,salary) e
group by e.emp_no having t > 15;
运行时间:27ms
占用内存:3308k
8、找出所有员工当前(to_date=’9999-01-01′)具体的薪水salary情况,对于相同的薪水只显示一次,并按照逆序显示
表结构说明
CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`from_date`));
脚本 1
select distinct salary
from salaries
where to_date='9999-01-01'
order by salary desc;
运行时间:15ms
占用内存:3552k
脚本 2
select salary
from salaries
where to_date='9999-01-01'
group by salary
order by salary desc;
运行时间:29ms
占用内存:3424k
备注:大家可以参考一下这个网址(https://www.jianshu.com/p/34800d06f63d)关于distinct和group by的效率分析
9、获取所有部门当前manager的当前薪水情况,给出dept_no, emp_no以及salary,当前表示to_date=’9999-01-01′
表结构说明
CREATE TABLE `dept_manager` (
`dept_no` char(4) NOT NULL,
`emp_no` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));
CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`from_date`));
脚本 1
select m.dept_no, m.emp_no, s.salary
from dept_manager m, salaries s
where m.to_date='9999-01-01'
and s.to_date='9999-01-01'
and m.emp_no = s.emp_no;
运行时间:19ms
占用内存:3320k
脚本 2
select m.dept_no, m.emp_no, s.salary
from dept_manager m
inner join salaries s
on m.to_date='9999-01-01'
and s.to_date='9999-01-01'
and m.emp_no = s.emp_no;
运行时间:20ms
占用内存:3428k
10、获取所有非manager的员工emp_no
表结构说明
CREATE TABLE `dept_manager` (
`dept_no` char(4) NOT NULL,
`emp_no` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));
CREATE TABLE `employees` (
`emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));
脚本 1
select emp_no
from employees
where emp_no not in (select emp_no from dept_manager);
运行时间:24ms
占用内存:3428k
脚本 2
select e.emp_no
from employees e
left join dept_manager m on e.emp_no = m.emp_no
where m.emp_no is null;
运行时间:14ms
占用内存:3420k
脚本 3
select emp_no
from employees
except select emp_no from dept_manager;
运行时间:26ms
占用内存:3428k
脚本 4
select e.emp_no
from employees e
where not exists (select emp_no
from dept_manager m
where m.emp_no = e.emp_no);
运行时间:19ms
占用内存:3192k
备注:看运行时间可以看出,join > exists > in > except
11、获取所有员工当前的manager,如果当前的manager是自己的话结果不显示,当前表示to_date=’9999-01-01’。结果第一列给出当前员工的emp_no,第二列给出其manager对应的manager_no。
表结构说明
CREATE TABLE `dept_emp` (
`emp_no` int(11) NOT NULL,
`dept_no` char(4) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));
CREATE TABLE `dept_manager` (
`dept_no` char(4) NOT NULL,
`emp_no` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));
脚本 1
select e.emp_no, m.emp_no as manager_no
from dept_emp e
inner join dept_manager m
on m.dept_no = e.dept_no
and m.to_date='9999-01-01'
and e.emp_no <> m.emp_no;
运行时间:25ms
占用内存:4440k
脚本 2
select e.emp_no, m.emp_no as manager_no
from dept_emp e
left join dept_manager m on m.dept_no = e.dept_no
where m.to_date='9999-01-01'
and m.emp_no != e.emp_no;
运行时间:28ms
占用内存:3432k
12、获取所有部门中当前员工薪水最高的相关信息,给出dept_no, emp_no以及其对应的salary, 当前表示to_date=’9999-01-01′
表结构说明
CREATE TABLE `dept_emp` (
`emp_no` int(11) NOT NULL,
`dept_no` char(4) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));
CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`from_date`));
脚本 1
select e.dept_no, s.emp_no, s.salary
from salaries s
inner join dept_emp e on e.emp_no = s.emp_no
where e.to_date='9999-01-01'
group by e.dept_no having max(s.salary);
运行时间:28ms
占用内存:3432k
脚本 2
select e.dept_no, s.emp_no, s.salary
from salaries s
left join dept_emp e on e.emp_no = s.emp_no
where e.to_date='9999-01-01'
group by e.dept_no having max(s.salary);
运行时间:24ms
占用内存:3300k
脚本 3
select e.dept_no, s.emp_no, max(s.salary)
from salaries s
left join dept_emp e on e.emp_no = s.emp_no
where e.to_date='9999-01-01'
group by e.dept_no;
运行时间:20ms
占用内存:3336k
13、从titles表获取按照title进行分组,每组个数大于等于2,给出title以及对应的数目t。
表结构说明
CREATE TABLE IF NOT EXISTS "titles" (
`emp_no` int(11) NOT NULL,
`title` varchar(50) NOT NULL,
`from_date` date NOT NULL,
`to_date` date DEFAULT NULL);
脚本 1
select title, count(title) as t
from titles
group by title having t >= 2;
运行时间:20ms
占用内存:3320k
14、从titles表获取按照title进行分组,每组个数大于等于2,给出title以及对应的数目t。 注意对于重复的emp_no进行忽略。
表结构说明
CREATE TABLE IF NOT EXISTS "titles" (
`emp_no` int(11) NOT NULL,
`title` varchar(50) NOT NULL,
`from_date` date NOT NULL,
`to_date` date DEFAULT NULL);
脚本 1
select title, count(distinct emp_no) as t
from titles
group by title having t >= 2;
运行时间:24ms
占用内存:3428k
脚本 2
select title, count(*) as t
from (select distinct emp_no, title from titles)
group by title having t >= 2;
运行时间:32ms
占用内存:3420k
15、查找employees表所有emp_no为奇数,且last_name不为Mary的员工信息,并按照hire_date逆序排列
表结构说明
CREATE TABLE `employees` (
`emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));
脚本 1
select *
from employees
where last_name != 'Mary'
and emp_no % 2 = 1
order by hire_date desc;
运行时间:28ms
占用内存:3404k
16、统计出当前各个title类型对应的员工当前薪水对应的平均工资。结果给出title以及平均工资avg。
表结构说明
CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`from_date`));
CREATE TABLE IF NOT EXISTS "titles" (
`emp_no` int(11) NOT NULL,
`title` varchar(50) NOT NULL,
`from_date` date NOT NULL,
`to_date` date DEFAULT NULL);
脚本 1
select t.title, avg(s.salary)
from salaries s
inner join titles t on s.emp_no = t.emp_no and s.to_date='9999-01-01' and t.to_date='9999-01-01'
group by t.title;
运行时间:30ms
占用内存:3224k
脚本 2
select t.title, avg(s.salary)
from salaries s
inner join titles t on s.emp_no = t.emp_no
where s.to_date='9999-01-01' and t.to_date='9999-01-01'
group by t.title;
运行时间:24ms
占用内存:3296k
17、获取当前(to_date=’9999-01-01’)薪水第二多的员工的emp_no以及其对应的薪水salary
表结构说明
CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`from_date`));
脚本 1
select emp_no, salary
from salaries
where to_date='9999-01-01'
and salary = (select distinct salary from salaries order by salary desc limit 1,1);
运行时间:25ms
占用内存:3548k
18、查找当前薪水(to_date=’9999-01-01′)排名第二多的员工编号emp_no、薪水salary、last_name以及first_name,不准使用order by
表结构说明
CREATE TABLE `employees` (
`emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));
CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`from_date`));
脚本 1
select e.emp_no, max(s.salary), e.last_name, e.first_name
from salaries s
left join employees e on s.emp_no = e.emp_no
where s.to_date='9999-01-01'
and salary < (select max(salary) from salaries where to_date='9999-01-01');
运行时间:27ms
占用内存:3420k
脚本 2
select e.emp_no, max(s.salary), e.last_name, e.first_name
from salaries s, employees e
where s.emp_no = e.emp_no
and s.to_date='9999-01-01'
and salary < (select max(salary) from salaries where to_date='9999-01-01');
运行时间:16ms
占用内存:3416k
脚本 3
select e.emp_no, s.salary, e.last_name, e.first_name
from salaries s inner join employees e on s.emp_no = e.emp_no
where s.to_date='9999-01-01'
and salary = (
select max(salary)
from salaries
where to_date='9999-01-01'
and salary < (
select max(salary)
from salaries
where to_date='9999-01-01')
);
运行时间:15ms
占用内存:3420k
脚本 4
select e.emp_no, salary, last_name, first_name
from employees as e inner join salaries as s on e.emp_no = s.emp_no
where s.to_date='9999-01-01'
and salary = (select max(salary)
from salaries
where to_date='9999-01-01'
and salary < (select max(salary) from salaries where to_date='9999-01-01'));
运行时间:22ms
占用内存:3292k
脚本 5
select e.emp_no, s.salary, e.last_name, e.first_name
from salaries s, employees e
where s.to_date='9999-01-01'
and s.emp_no = e.emp_no
and salary = (
select max(salary)
from salaries
where to_date='9999-01-01'
and salary < (
select max(salary)
from salaries
where to_date='9999-01-01')
);
运行时间:19ms
占用内存:3320k
19、查找所有员工的last_name和first_name以及对应的dept_name,也包括暂时没有分配部门的员工
表结构说明
CREATE TABLE `departments` (
`dept_no` char(4) NOT NULL,
`dept_name` varchar(40) NOT NULL,
PRIMARY KEY (`dept_no`));
CREATE TABLE `dept_emp` (
`emp_no` int(11) NOT NULL,
`dept_no` char(4) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));
CREATE TABLE `employees` (
`emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));
脚本 1
select e.last_name, e.first_name, d.dept_name
from employees e
left join dept_emp de on de.emp_no = e.emp_no
left join departments d on d.dept_no = de.dept_no;
运行时间:27ms
占用内存:3320k
脚本 2
select e.last_name, e.first_name, tmp.dept_name
from employees e
left join (select d.dept_name, de.emp_no
from dept_emp de
left join departments d
on d.dept_no = de.dept_no) tmp
on tmp.emp_no = e.emp_no;
运行时间:23ms
占用内存:3684k
20、查找员工编号emp_no为10001其自入职以来的薪水salary涨幅值growth
表结构说明
CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`from_date`));
脚本 1
select (max(salary) - min(salary)) as growth
from salaries
where emp_no=10001;
运行时间:18ms
占用内存:3320k
脚本 2
select (
(select salary from salaries where emp_no=10001 order by to_date desc limit 1) -
(select salary from salaries where emp_no=10001 order by to_date asc limit 1)
) as growth
运行时间:23ms
占用内存:3448k
21、查找所有员工自入职以来的薪水涨幅情况,给出员工编号emp_no以及其对应的薪水涨幅growth,并按照growth进行升序
表结构说明
CREATE TABLE `employees` (
`emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));
CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`from_date`));
脚本 1
select current.emp_no, (current.salary - start.salary) as growth
from (
select e1.emp_no, s1.salary
from employees e1
left join salaries s1 on e1.emp_no = s1.emp_no
where s1.to_date = '9999-01-01'
) as current
inner join (
select e2.emp_no, s2.salary
from employees e2
left join salaries s2 on e2.emp_no = s2.emp_no
where e2.hire_date = s2.from_date
) as start on start.emp_no = current.emp_no
order by growth;
运行时间:25ms
占用内存:3304k
脚本 2
select current.emp_no, (current.salary - start.salary) as growth
from (
select e2.emp_no, s2.salary
from employees e2
left join salaries s2 on e2.emp_no = s2.emp_no
where e2.hire_date = s2.from_date
) as start
inner join (
select emp_no, salary
from salaries
where to_date = '9999-01-01'
) as current
on start.emp_no = current.emp_no
order by growth;
运行时间:21ms
占用内存:3260k
脚本 3
SELECT sCurrent.emp_no, (sCurrent.salary-sStart.salary) AS growth
FROM
(SELECT s.emp_no, s.salary
FROM employees e, salaries s
WHERE e.emp_no = s.emp_no
AND s.to_date = '9999-01-01') AS sCurrent,
(SELECT s.emp_no, s.salary
FROM employees e, salaries s
WHERE e.emp_no = s.emp_no
AND s.from_date = e.hire_date) AS sStart
WHERE sCurrent.emp_no = sStart.emp_no
ORDER BY growth
运行时间:21ms
占用内存:3312k
脚本 4
SELECT sCurrent.emp_no, (sCurrent.salary-sStart.salary) AS growth
FROM
(SELECT s.emp_no, s.salary
FROM employees e, salaries s
WHERE e.emp_no = s.emp_no
AND s.from_date = e.hire_date) AS sStart,
(SELECT emp_no, salary
FROM salaries
WHERE to_date = '9999-01-01') AS sCurrent
WHERE sCurrent.emp_no = sStart.emp_no
ORDER BY growth
运行时间:21ms
占用内存:3308k
22、统计各个部门对应员工涨幅的次数总和,给出部门编码dept_no、部门名称dept_name以及次数sum
表结构说明
CREATE TABLE `departments` (
`dept_no` char(4) NOT NULL,
`dept_name` varchar(40) NOT NULL,
PRIMARY KEY (`dept_no`));
CREATE TABLE `dept_emp` (
`emp_no` int(11) NOT NULL,
`dept_no` char(4) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));
CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`from_date`));
脚本 1
select de.dept_no, d.dept_name, count(s.salary) as sum
from dept_emp de
left join salaries s on de.emp_no = s.emp_no
left join departments d on de.dept_no = d.dept_no
group by de.dept_no;
运行时间:14ms
占用内存:3420k
脚本 2
select de.dept_no, d.dept_name, count(s.salary) as sum
from dept_emp de, salaries s, departments d
where de.emp_no = s.emp_no
and de.dept_no = d.dept_no
group by de.dept_no;
运行时间:14ms
占用内存:3420k
23、对所有员工的当前(to_date=’9999-01-01′)薪水按照salary进行按照1-N的排名,相同salary并列且按照emp_no升序排列
表结构说明
CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`from_date`));
脚本 1
select s1.emp_no, s1.salary, count(distinct s2.salary) as rank
from salaries s1, salaries s2
where s1.to_date='9999-01-01'
and s2.to_date='9999-01-01'
and s1.salary <= s2.salary
group by s1.emp_no
order by s1.salary desc, s2.emp_no asc;
运行时间:15ms
占用内存:3556k
24、获取所有非manager员工当前的薪水情况,给出dept_no、emp_no以及salary ,当前表示to_date=’9999-01-01′
表结构说明
CREATE TABLE `dept_emp` (
`emp_no` int(11) NOT NULL,
`dept_no` char(4) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));
CREATE TABLE `dept_manager` (
`dept_no` char(4) NOT NULL,
`emp_no` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));
CREATE TABLE `employees` (
`emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));
CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`from_date`));
脚本 1
select de.dept_no, e.emp_no, s.salary
from employees e
inner join salaries s on e.emp_no = s.emp_no and s.to_date = '9999-01-01'
inner join dept_emp de on de.emp_no = e.emp_no
left join dept_manager dm on e.emp_no = dm.emp_no
where dm.dept_no is null;
运行时间:23ms
占用内存:3300k
脚本 2
select de.dept_no, ee.emp_no, s.salary
from (select e.emp_no
from employees e
left join dept_manager dm on dm.emp_no = e.emp_no
where dm.dept_no is null) as ee
inner join salaries s on ee.emp_no = s.emp_no and s.to_date = '9999-01-01'
inner join dept_emp de on ee.emp_no = de.emp_no;
运行时间:15ms
占用内存:3424k
25、获取员工其当前的薪水比其manager当前薪水还高的相关信息,当前表示to_date=’9999-01-01′,结果第一列给出员工的emp_no,第二列给出其manager的manager_no,第三列给出该员工当前的薪水emp_salary,第四列给该员工对应的manager当前的薪水manager_salary
表结构说明
CREATE TABLE `dept_emp` (
`emp_no` int(11) NOT NULL,
`dept_no` char(4) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));
CREATE TABLE `dept_manager` (
`dept_no` char(4) NOT NULL,
`emp_no` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));
CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`from_date`));
脚本 1
select de.emp_no as emp_no, dm.emp_no as manager_no, de.salary as emp_salary, dm.salary as manager_salary
from (select e.dept_no, e.emp_no, s.salary
from dept_emp e
inner join salaries s on e.emp_no = s.emp_no and s.to_date='9999-01-01') as de
inner join (select m.dept_no, m.emp_no, s.salary from dept_manager m
inner join salaries s on m.emp_no = s.emp_no and s.to_date='9999-01-01')
as dm on de.dept_no = dm.dept_no
where emp_salary > manager_salary and de.dept_no = dm.dept_no;
运行时间:19ms
占用内存:3304k
26、汇总各个部门当前员工的title类型的分配数目,结果给出部门编号dept_no、dept_name、其当前员工所有的title以及该类型title对应的数目count
表结构说明
CREATE TABLE `departments` (
`dept_no` char(4) NOT NULL,
`dept_name` varchar(40) NOT NULL,
PRIMARY KEY (`dept_no`));
CREATE TABLE `dept_emp` (
`emp_no` int(11) NOT NULL,
`dept_no` char(4) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));
CREATE TABLE IF NOT EXISTS `titles` (
`emp_no` int(11) NOT NULL,
`title` varchar(50) NOT NULL,
`from_date` date NOT NULL,
`to_date` date DEFAULT NULL);
脚本 1
select d.dept_no, d.dept_name, t.title, count(*) as count
from titles t
inner join dept_emp e on e.emp_no = t.emp_no and e.to_date='9999-01-01' and t.to_date='9999-01-01'
inner join departments d on e.dept_no = d.dept_no
group by d.dept_no, t.title;
运行时间:26ms
占用内存:3292k
27、给出每个员工每年薪水涨幅超过5000的员工编号emp_no、薪水变更开始日期from_date以及薪水涨幅值salary_growth,并按照salary_growth逆序排列。
提示:在sqlite中获取datetime时间对应的年份函数为strftime(‘%Y’, to_date)
表结构说明
CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`from_date`));
脚本 1
select s2.emp_no, s2.from_date, (s2.salary - s1.salary) as salary_growth
from salaries s1, salaries s2
where s1.emp_no = s2.emp_no
and salary_growth > 5000
and (strftime('%Y', s2.from_date) - strftime('%Y', s1.from_date) = 1 or
strftime('%Y', s2.to_date) - strftime('%Y', s1.to_date) = 1)
order by salary_growth desc;
运行时间:23ms
占用内存:3416k
脚本 2
select s2.emp_no, s2.from_date, (s2.salary - s1.salary) as salary_growth
from salaries s1
inner join salaries s2 on s1.emp_no = s2.emp_no
and (strftime('%Y', s2.from_date) - strftime('%Y', s1.from_date) = 1 or
strftime('%Y', s2.to_date) - strftime('%Y', s1.to_date) = 1)
where salary_growth > 5000
order by salary_growth desc;
运行时间:20ms
占用内存:3300k
28、查找描述信息中包括robot的电影对应的分类名称以及电影数目,而且还需要该分类对应电影数量>=5部
表结构说明
CREATE TABLE IF NOT EXISTS film (
film_id smallint(5) NOT NULL DEFAULT '0',
title varchar(255) NOT NULL,
description text,
PRIMARY KEY (film_id));
CREATE TABLE category (
category_id tinyint(3) NOT NULL ,
name varchar(25) NOT NULL, `last_update` timestamp,
PRIMARY KEY ( category_id ));
CREATE TABLE film_category (
film_id smallint(5) NOT NULL,
category_id tinyint(3) NOT NULL, `last_update` timestamp);
脚本 1
select c.name, count(f.film_id) as count
from film f, film_category fc, category c,
(select category_id from film_category group by category_id having count(category_id) >= 5) as cc
where f.description like "%robot%"
and f.film_id = fc.film_id
and fc.category_id = c.category_id
and c.category_id = cc.category_id
运行时间:27ms
占用内存:3556k
29、使用join查询方式找出没有分类的电影id以及名称
表结构说明
CREATE TABLE IF NOT EXISTS film (
film_id smallint(5) NOT NULL DEFAULT '0',
title varchar(255) NOT NULL,
description text,
PRIMARY KEY (film_id));
CREATE TABLE category (
category_id tinyint(3) NOT NULL ,
name varchar(25) NOT NULL, `last_update` timestamp,
PRIMARY KEY ( category_id ));
CREATE TABLE film_category (
film_id smallint(5) NOT NULL,
category_id tinyint(3) NOT NULL, `last_update` timestamp);
脚本 1
select f.film_id, f.title
from film f
left join film_category fc on fc.film_id = f.film_id
where fc.category_id is null;
运行时间:25ms
占用内存:3556k
30、使用子查询的方式找出属于Action分类的所有电影对应的title,description
表结构说明
CREATE TABLE IF NOT EXISTS film (
film_id smallint(5) NOT NULL DEFAULT '0',
title varchar(255) NOT NULL,
description text,
PRIMARY KEY (film_id));
CREATE TABLE category (
category_id tinyint(3) NOT NULL ,
name varchar(25) NOT NULL, `last_update` timestamp,
PRIMARY KEY ( category_id ));
CREATE TABLE film_category (
film_id smallint(5) NOT NULL,
category_id tinyint(3) NOT NULL, `last_update` timestamp);
脚本 1
select title, description
from film
where film_id in
(select film_id
from film_category
where category_id in
(select category_id from category where name="Action")
);
运行时间:25ms
占用内存:3432k
脚本 2
select title, description
from film
where film_id in
(select fc.film_id
from film_category fc
inner join category c
on c.category_id = fc.category_id
and c.name="Action");
运行时间:27ms
占用内存:3552k
脚本 3
使用非子查询的方式找出属于Action分类的所有电影对应的title,description
select f.title, f.description
from film f
left join film_category fc on fc.film_id = f.film_id
left join category c on c.category_id = fc.category_id
where c.name = "Action";
运行时间:28ms
占用内存:3448k
31、获取select * from employees对应的执行计划
脚本 1
explain select * from employees;
运行时间:19ms
占用内存:3300k
32、将employees表的所有员工的last_name和first_name拼接起来作为Name,中间以一个空格区分
表结构说明
CREATE TABLE `employees` (
`emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));
脚本 1
sqlite3
SELECT last_name||' '||first_name AS Name FROM employees
运行时间:19ms
占用内存:3300k
脚本 2
mysql、oracle、sql server
SELECT concat(last_name, " ", first_name) AS Name FROM employees
33、创建一个actor表,包含如下列信息
表结构说明
列表 类型 是否为NULL 含义
actor_id smallint(5) not null 主键id
first_name varchar(45) not null 名字
last_name varchar(45) not null 姓氏
last_update timestamp not null 最后更新时间,默认是系统的当前时间
脚本 1
CREATE TABLE `actor` (
`actor_id` smallint(5) NOT NULL,
`first_name` varchar(45) NOT NULL,
`last_name` varchar(45) NOT NULL,
`last_update` timestamp NOT NULL default (datetime('now','localtime')),
PRIMARY KEY (`actor_id`)
);
运行时间:19ms
占用内存:3292k
34、对于表actor批量插入如下数据
表结构说明
CREATE TABLE IF NOT EXISTS actor (
actor_id smallint(5) NOT NULL PRIMARY KEY,
first_name varchar(45) NOT NULL,
last_name varchar(45) NOT NULL,
last_update timestamp NOT NULL DEFAULT (datetime('now','localtime')))
数据
actor_id first_name last_name last_update
1 PENELOPE GUINESS 2006-02-15 12:34:33
2 NICK WAHLBERG 2006-02-15 12:34:33
脚本 1
insert into actor values(1, 'PENELOPE', 'GUINESS', '2006-02-15 12:34:33'),(2, 'NICK', 'WAHLBERG', '2006-02-15 12:34:33');
运行时间:19ms
占用内存:3420k
35、对于表actor批量插入如下数据,如果数据已经存在,请忽略,不使用replace操作
表结构说明
CREATE TABLE IF NOT EXISTS actor (
actor_id smallint(5) NOT NULL PRIMARY KEY,
first_name varchar(45) NOT NULL,
last_name varchar(45) NOT NULL,
last_update timestamp NOT NULL DEFAULT (datetime('now','localtime')))
数据
actor_id first_name last_name last_update
'3' 'ED' 'CHASE' '2006-02-15 12:34:33'
脚本 1
insert or ignore into actor values(3, 'ED', 'CHASE', '2006-02-15 12:34:33');
运行时间:23ms
占用内存:4332k
36、对于表actor批量插入如下数据,如果数据已经存在,请忽略,不使用replace操作
表结构说明
CREATE TABLE IF NOT EXISTS actor (
actor_id smallint(5) NOT NULL PRIMARY KEY,
first_name varchar(45) NOT NULL,
last_name varchar(45) NOT NULL,
last_update timestamp NOT NULL DEFAULT (datetime('now','localtime')))
数据
actor_id first_name last_name last_update
'3' 'ED' 'CHASE' '2006-02-15 12:34:33'
脚本 1
insert or ignore into actor values(3, 'ED', 'CHASE', '2006-02-15 12:34:33');
运行时间:23ms
占用内存:4332k
37、创建一个actor_name表,将actor表中的所有first_name以及last_name导入改表。
对于如下表actor,其对应的数据为:
actor_id first_name last_name last_update
1 PENELOPE GUINESS 2006-02-15 12:34:33
2 NICK WAHLBERG 2006-02-15 12:34:33
actor_name表结构如下:
列表 类型 是否为NULL 含义
first_name varchar(45) not null 名字
last_name varchar(45) not null 姓氏
脚本 1
create table actor_name as select first_name, last_name from actor;
运行时间:24ms
占用内存:3424k
脚本 2
create table actor_name(
first_name varchar(45) NOT NULL,
last_name varchar(45) NOT NULL
);
insert into actor_name select first_name, last_name from actor;
运行时间:18ms
占用内存:3292k
38、针对如下表actor结构创建索引,对first_name创建唯一索引uniq_idx_firstname,对last_name创建普通索引idx_lastname
表结构说明
CREATE TABLE IF NOT EXISTS actor (
actor_id smallint(5) NOT NULL PRIMARY KEY,
first_name varchar(45) NOT NULL,
last_name varchar(45) NOT NULL,
last_update timestamp NOT NULL DEFAULT (datetime('now','localtime')))
脚本 1
create unique index uniq_idx_firstname on actor(first_name);
create index idx_lastname on actor(last_name);
运行时间:24ms
占用内存:3208k
39、针对actor表创建视图actor_name_view,只包含first_name以及last_name两列,并对这两列重新命名,first_name为first_name_v,last_name修改为last_name_v
表结构说明
CREATE TABLE IF NOT EXISTS actor (
actor_id smallint(5) NOT NULL PRIMARY KEY,
first_name varchar(45) NOT NULL,
last_name varchar(45) NOT NULL,
last_update timestamp NOT NULL DEFAULT (datetime('now','localtime')))
脚本 1
create view actor_name_view as select first_name as first_name_v, last_name as last_name_v from actor;
运行时间:20ms
占用内存:3296k
脚本 2
create view actor_name_view(first_name_v, last_name_v) as select first_name, last_name from actor;
运行时间:21ms
占用内存:3428k
40、针对salaries表emp_no字段创建索引idx_emp_no,查询emp_no为10005, 使用强制索引。
表结构说明
CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`from_date`));
create index idx_emp_no on salaries(emp_no);
脚本 1
sqlite3
select * from salaries indexed by idx_emp_no where emp_no = 10005;
运行时间:29ms
占用内存:3428k
参考:http://www.runoob.com/sqlite/sqlite-indexed-by.html
脚本 2
mysql、oracle、sql
select * from salaries force index idx_emp_no where emp_no = 10005
运行时间:21ms
占用内存:3428k
参考:http://www.jb51.net/article/49807.htm
41、存在actor表,现在在last_update后面新增加一列名字为create_date, 类型为datetime, NOT NULL,默认值为’0000-00-00 00:00:00′
表结构说明
CREATE TABLE IF NOT EXISTS actor (
actor_id smallint(5) NOT NULL PRIMARY KEY,
first_name varchar(45) NOT NULL,
last_name varchar(45) NOT NULL,
last_update timestamp NOT NULL DEFAULT (datetime('now','localtime')));
脚本 1
alter table actor add create_date datetime NOT NULL default '0000-00-00 00:00:00';
运行时间:24ms
占用内存:3312k
42、构造一个触发器audit_log,在向employees_test表中插入一条数据的时候,触发插入相关的数据到audit中。
表结构说明
CREATE TABLE employees_test(
ID INT PRIMARY KEY NOT NULL,
NAME TEXT NOT NULL,
AGE INT NOT NULL,
ADDRESS CHAR(50),
SALARY REAL
);
CREATE TABLE audit(
EMP_no INT NOT NULL,
NAME TEXT NOT NULL
);
脚本 1
create trigger audit_log after insert on employees_test
begin
insert into audit values(new.id, new.name);
end;
运行时间:22ms
占用内存:3436k
43、删除emp_no重复的记录,只保留最小的id对应的记录。
表结构说明
CREATE TABLE IF NOT EXISTS titles_test (
id int(11) not null primary key,
emp_no int(11) NOT NULL,
title varchar(50) NOT NULL,
from_date date NOT NULL,
to_date date DEFAULT NULL);
insert into titles_test values
('1', '10001', 'Senior Engineer', '1986-06-26', '9999-01-01'),
('2', '10002', 'Staff', '1996-08-03', '9999-01-01'),
('3', '10003', 'Senior Engineer', '1995-12-03', '9999-01-01'),
('4', '10004', 'Senior Engineer', '1995-12-03', '9999-01-01'),
('5', '10001', 'Senior Engineer', '1986-06-26', '9999-01-01'),
('6', '10002', 'Staff', '1996-08-03', '9999-01-01'),
('7', '10003', 'Senior Engineer', '1995-12-03', '9999-01-01');
脚本 1
delete from titles_test where id not in (select min(id) from titles_test group by emp_no);
运行时间:20ms
占用内存:3320k
脚本 2
delete from titles_test
where id in (
select a.id
from titles_test a, titles_test b
where a.emp_no = b.emp_no
and a.id > b.id);
运行时间:22ms
占用内存:3552k
44、将所有to_date为9999-01-01的全部更新为NULL,且 from_date更新为2001-01-01。
表结构说明
CREATE TABLE IF NOT EXISTS titles_test (
id int(11) not null primary key,
emp_no int(11) NOT NULL,
title varchar(50) NOT NULL,
from_date date NOT NULL,
to_date date DEFAULT NULL);
insert into titles_test values
('1', '10001', 'Senior Engineer', '1986-06-26', '9999-01-01'),
('2', '10002', 'Staff', '1996-08-03', '9999-01-01'),
('3', '10003', 'Senior Engineer', '1995-12-03', '9999-01-01'),
('4', '10004', 'Senior Engineer', '1995-12-03', '9999-01-01'),
('5', '10001', 'Senior Engineer', '1986-06-26', '9999-01-01'),
('6', '10002', 'Staff', '1996-08-03', '9999-01-01'),
('7', '10003', 'Senior Engineer', '1995-12-03', '9999-01-01');
脚本 1
update titles_test set to_date = null, from_date='2001-01-01' where to_date='9999-01-01';
运行时间:22ms
占用内存:3328k
45、将id=5以及emp_no=10001的行数据替换成id=5以及emp_no=10005,其他数据保持不变,使用replace实现。
表结构说明
CREATE TABLE IF NOT EXISTS titles_test (
id int(11) not null primary key,
emp_no int(11) NOT NULL,
title varchar(50) NOT NULL,
from_date date NOT NULL,
to_date date DEFAULT NULL);
insert into titles_test values
('1', '10001', 'Senior Engineer', '1986-06-26', '9999-01-01'),
('2', '10002', 'Staff', '1996-08-03', '9999-01-01'),
('3', '10003', 'Senior Engineer', '1995-12-03', '9999-01-01'),
('4', '10004', 'Senior Engineer', '1995-12-03', '9999-01-01'),
('5', '10001', 'Senior Engineer', '1986-06-26', '9999-01-01'),
('6', '10002', 'Staff', '1996-08-03', '9999-01-01'),
('7', '10003', 'Senior Engineer', '1995-12-03', '9999-01-01');
脚本 1
replace into titles_test values('5', '10005', 'Senior Engineer', '1986-06-26', '9999-01-01');
运行时间:23ms
占用内存:3330k
脚本 2
update titles_test set emp_no = replace(emp_no, 10001, 10005) where emp_no = 10001;
运行时间:21ms
占用内存:3304k
45、将titles_test表名修改为titles_2017。
表结构说明
CREATE TABLE IF NOT EXISTS titles_test (
id int(11) not null primary key,
emp_no int(11) NOT NULL,
title varchar(50) NOT NULL,
from_date date NOT NULL,
to_date date DEFAULT NULL);
insert into titles_test values
('1', '10001', 'Senior Engineer', '1986-06-26', '9999-01-01'),
('2', '10002', 'Staff', '1996-08-03', '9999-01-01'),
('3', '10003', 'Senior Engineer', '1995-12-03', '9999-01-01'),
('4', '10004', 'Senior Engineer', '1995-12-03', '9999-01-01'),
('5', '10001', 'Senior Engineer', '1986-06-26', '9999-01-01'),
('6', '10002', 'Staff', '1996-08-03', '9999-01-01'),
('7', '10003', 'Senior Engineer', '1995-12-03', '9999-01-01');
脚本 1
alter table titles_test rename to titles_2017;
运行时间:18ms
占用内存:3192k
脚本 2
mysql、oracle、sql
rename table titles_test to titles_2017;
运行时间:21ms
占用内存:3304k
45、在audit表上创建外键约束,其emp_no对应employees_test表的主键id。
表结构说明
CREATE TABLE employees_test(
ID INT PRIMARY KEY NOT NULL,
NAME TEXT NOT NULL,
AGE INT NOT NULL,
ADDRESS CHAR(50),
SALARY REAL
);
CREATE TABLE audit(
EMP_no INT NOT NULL,
create_date datetime NOT NULL
);
脚本 1
DROP TABLE audit;
CREATE TABLE audit(
EMP_no INT NOT NULL,
create_date datetime NOT NULL,
FOREIGN KEY(EMP_no) REFERENCES employees_test(ID));
运行时间:20ms
占用内存:3568k
46、如何获取emp_v和employees有相同的数据?
表结构说明
create view emp_v as select * from employees where emp_no >10005;
CREATE TABLE `employees` (
`emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));
脚本 1
select em.* from employees em, emp_v ev where em.emp_no = ev.emp_no;
运行时间:18ms
占用内存:3312k
脚本 2
select * from employees intersect select * from emp_v;
运行时间:23ms
占用内存:3552k
脚本 3
select * from emp_v;
运行时间:22ms
占用内存:3300k
47、将所有获取奖金的员工当前的薪水增加10%。
表结构说明
create table emp_bonus(
`emp_no` int not null,
`recevied` datetime not null,
`btype` smallint not null);
CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL, PRIMARY KEY (`emp_no`,`from_date`));
脚本 1
update salaries set salary = salary * 1.1
where emp_no in (select emp_no from emp_bonus);
运行时间:24ms
占用内存:3412k
48、针对库中的所有表生成select count(*)对应的SQL语句
表结构说明
CREATE TABLE `employees` (
`emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));
create table emp_bonus(
`emp_no` int not null,
`recevied` datetime not null,
`btype` smallint not null);
CREATE TABLE `dept_emp` (
`emp_no` int(11) NOT NULL,
`dept_no` char(4) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));
CREATE TABLE `dept_manager` (
`dept_no` char(4) NOT NULL,
`emp_no` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));
CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`from_date`));
脚本 1
select "select count(*) from "||name||";" as cnts
from sqlite_master
where type='table'
运行时间:23ms
占用内存:3420k
49、将employees表中的所有员工的last_name和first_name通过(‘)连接起来
表结构说明
CREATE TABLE `employees` (
`emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));
脚本 1
select last_name||"'"||first_name from employees;
运行时间:25ms
占用内存:3320k
49、将employees表中的所有员工的last_name和first_name通过(‘)连接起来
表结构说明
CREATE TABLE `employees` (
`emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));
脚本 1
select last_name||"'"||first_name from employees;
运行时间:25ms
占用内存:3320k
脚本 2
select concat(last_name, "'", first_name) from employees;
运行时间:25ms
占用内存:3320k
50、查找字符串’10,A,B’ 中逗号’,’出现的次数cnt。
脚本 1
select (length('10,A,B') - length(replace('10,A,B', ',', ''))) / length(',') as cnt;
运行时间:19ms
占用内存:3292k
51、获取Employees中的first_name,查询按照first_name最后两个字母,按照升序进行排列
表结构说明
CREATE TABLE `employees` (
`emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));
脚本 1
select first_name from employees order by substr(first_name, -2)
运行时间:14ms
占用内存:3296k
脚本 2
select first_name
from employees
order by substr(first_name, length(first_name) - 1)
运行时间:15ms
占用内存:3296k
52、按照dept_no进行汇总,属于同一个部门的emp_no按照逗号进行连接,结果给出dept_no以及连接出的结果employees
表结构说明
CREATE TABLE `dept_emp` (
`emp_no` int(11) NOT NULL,
`dept_no` char(4) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));
脚本 1
select dept_no, group_concat(emp_no) as employees
from dept_emp
group by dept_no;
运行时间:14ms
占用内存:3308k
53、查找排除当前最大、最小salary之后的员工的平均工资avg_salary。
表结构说明
CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`from_date`));
脚本 1
select avg(salary) as avg_salary
from salaries
where to_date='9999-01-01'
and salary not in (select min(salary) from salaries)
and salary not in (select max(salary) from salaries);
运行时间:21ms
占用内存:3408k
备注:这个居然通过了,应该是下面的那个带有日期的才是正确的
脚本 2
select avg(salary) as avg_salary
from salaries
where to_date='9999-01-01'
and salary not in (select min(salary) from salaries where to_date='9999-01-01')
and salary not in (select max(salary) from salaries where to_date='9999-01-01');
运行时间:21ms
占用内存:3408k
备注:这个居然没有通过
54、分页查询employees表,每5行一页,返回第2页的数据
表结构说明
CREATE TABLE `employees` (
`emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));
脚本 1
select * from employees limit(2-1)*5, 5;
运行时间:15ms
占用内存:3292k
55、获取所有员工的emp_no、部门编号dept_no以及对应的bonus类型btype和recevied,没有分配具体的员工不显示
表结构说明
CREATE TABLE `dept_emp` (
`emp_no` int(11) NOT NULL,
`dept_no` char(4) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));
CREATE TABLE `dept_manager` (
`dept_no` char(4) NOT NULL,
`emp_no` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));
CREATE TABLE `employees` (
`emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));
CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`from_date`));
create table emp_bonus(
`emp_no` int not null,
`recevied` datetime not null,
`btype` smallint not null);
脚本 1
select e.emp_no, de.dept_no, b.btype, b.recevied
from employees e
inner join dept_emp de on de.emp_no = e.emp_no
left join emp_bonus as b on b.emp_no = e.emp_no;
运行时间:28ms
占用内存:3404k
脚本 2
select de.emp_no, de.dept_no, b.btype, b.recevied
from dept_emp de
left join emp_bonus as b on b.emp_no = de.emp_no;
运行时间:20ms
占用内存:3424k
56、使用含有关键字exists查找未分配具体部门的员工的所有信息
表结构说明
CREATE TABLE `employees` (
`emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));
CREATE TABLE `dept_emp` (
`emp_no` int(11) NOT NULL,
`dept_no` char(4) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));
脚本 1
select *
from employees e
where not exists (select emp_no from dept_emp de where e.emp_no=de.emp_no);
运行时间:20ms
占用内存:3300k
57、获取employees中的行数据,且这些行也存在于emp_v中。注意不能使用intersect关键字
表结构说明
create view emp_v as select * from employees where emp_no >10005;
CREATE TABLE `employees` (
`emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));
脚本 1
select e.* from employees e, emp_v ev where ev.emp_no = e.emp_no;
运行时间:22ms
占用内存:3288k
58、给出emp_no、first_name、last_name、奖金类型btype、对应的当前薪水情况salary以及奖金金额bonus
bonus类型btype为1其奖金为薪水salary的10%,btype为2其奖金为薪水的20%,其他类型均为薪水的30%。 当前薪水表示to_date=’9999-01-01′
表结构说明
CREATE TABLE `employees` (
`emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));
CREATE TABLE `dept_emp` (
`emp_no` int(11) NOT NULL,
`dept_no` char(4) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));
create table emp_bonus(
emp_no int not null,
recevied datetime not null,
btype smallint not null);
CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL, PRIMARY KEY (`emp_no`,`from_date`));
脚本 1
select e.emp_no, e.first_name, e.last_name, b.btype, s.salary, (
case b.btype
when 1 then s.salary * 0.1
when 2 then s.salary * 0.2
else s.salary * 0.3 end) as bonus
from employees e
inner join salaries s on s.emp_no = e.emp_no and s.to_date='9999-01-01'
inner join emp_bonus b on b.emp_no = e.emp_no;
运行时间:28ms
占用内存:3300k
59、按照salary的累计和running_total,其中running_total为前两个员工的salary累计和,其他以此类推
表结构说明
CREATE TABLE `salaries` ( `emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`from_date`));
脚本 1
select s1.emp_no, s1.salary, (
select sum(s2.salary)
from salaries s2
where s2.emp_no <= s1.emp_no
and s2.to_date='9999-01-01'
) as running_total
from salaries as s1
where s1.to_date='9999-01-01'
order by s1.emp_no;
运行时间:25ms
占用内存:3296k
脚本 2
select s.emp_no,s.salary,(
select sum(salary)
from salaries
where rowid<=s.rowid
and to_date ="9999-01-01") as running_total
from salaries s where s.to_date ="9999-01-01"
运行时间:25ms
占用内存:3424k
60、对于employees表中,在对first_name进行排名后,选出奇数排名对应的first_name
表结构说明
CREATE TABLE `employees` (
`emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));
脚本 1
select e1.first_name
from (
select e2.first_name,(
select count(*)
from employees as e3
where e3.first_name <= e2.first_name) as rowid
from employees as e2) as e1
where e1.rowid % 2 = 1;
运行时间:21ms
占用内存:3196k
脚本 2
select e1.first_name
from employees e1
where (select count(*)
from employees e2
where e1.first_name <= e2.first_name) % 2 = 1;
运行时间:20ms
占用内存:3292k